我想按距離排序我的數組。我已經擁有了一切能夠抓住距離的東西,但不確定如何從最接近最遠的用戶位置進行排序。我已經使用MKMapItem的下面的代碼,但不確定如何應用到我當前的數組。Swift Firebase按距離排序
func sortMapItems() {
self.mapItems = self.mapItems.sorted(by: { (b, a) -> Bool in
return self.userLocation.location!.distance(from: a.placemark.location!) > self.userLocation.location!.distance(from: b.placemark.location!)
})
}
火力地堡呼叫
databaseRef.child("Businesses").queryOrdered(byChild: "businessName").observe(.childAdded, with: { (snapshot) in
let key = snapshot.key
if(key == self.loggedInUser?.uid) {
print("Same as logged in user, so don't show!")
} else {
if let locationValue = snapshot.value as? [String: AnyObject] {
let lat = Double(locationValue["businessLatitude"] as! String)
let long = Double(locationValue["businessLongitude"] as! String)
let businessLocation = CLLocation(latitude: lat!, longitude: long!)
let latitude = self.locationManager.location?.coordinate.latitude
let longitude = self.locationManager.location?.coordinate.longitude
let userLocation = CLLocation(latitude: latitude!, longitude: longitude!)
let distanceInMeters : Double = userLocation.distance(from: businessLocation)
let distanceInMiles : Double = ((distanceInMeters.description as String).doubleValue * 0.00062137)
let distanceLabelText = "\(distanceInMiles.string(2)) miles away"
var singleChildDictionary = locationValue
singleChildDictionary["distanceLabelText"] = distanceLabelText as AnyObject
self.usersArray.append(singleChildDictionary as NSDictionary)
/*
func sortMapItems() {
self.mapItems = self.mapItems.sorted(by: { (b, a) -> Bool in
return self.userLocation.location!.distance(from: a.placemark.location!) > self.userLocation.location!.distance(from: b.placemark.location!)
})
}
*/
}
//insert the rows
self.followUsersTableView.insertRows(at: [IndexPath(row:self.usersArray.count-1,section:0)], with: UITableViewRowAnimation.automatic)
}
}) { (error) in
print(error.localizedDescription)
}
}
所以你要對我們進行排序根據distanceLabelText ersArray? – 3stud1ant3
是的,這將是完美的 –
你想在哪裏排序usersArray,爲什麼? – 3stud1ant3