轉換的Ruby代碼爲PHP幫助請

Question

的Ruby代碼：

# Turn hash input into JSON, store it in variable called "my_input" 
my_input = { "itemFilter" => { "keywords" => "milk" }}.to_json 
    # Open connection to website.com 
@http = Net::HTTP.new("website.com") 
    # Post the request to our API, with the "findItems" name and our JSON from above as the value 
response_code, data = @http.post("/requests", "findItems=#{my_input}", 
           {'X-CUSTOM-HEADER' => 'MYCUSTOMCODE'}) 
my_hash = Crack::JSON.parse(data) 
my_milk = my_hash["findItems"]["item"].first 

PHP代碼：

$requestBody = json_encode(array("itemFilter" => array("keywords" => "milk"))); 
$headers = array ('X-CUSTOM-HEADER: MYCODE'); 
$connection = curl_init(); 
curl_setopt($connection, CURLOPT_URL, 'website.com/request/findItems='); 
curl_setopt($connection, CURLOPT_HTTPHEADER, $headers); 
curl_setopt($connection, CURLOPT_POST, 1); 
curl_setopt($connection, CURLOPT_POSTFIELDS, $requestBody); 
curl_setopt($connection, CURLOPT_RETURNTRANSFER, 1); 
$response = curl_exec($connection); 
curl_close($connection); 
print_r($response); 

Answer 1

發現問題..感謝您的輸入。我把一個尾部的斜線放在不需要的地方，json_encode在編碼周圍加上了括號，並且不需要它們。

Answer 2

看看json_encode，json_decode和cURL擴展。