我想從下面的json中產生一個名稱,位置,電話和電子郵件的數據表。但我現在不知道如何訪問名稱和嵌套的值。更改json是不可能的。jquery datatables嵌套值json
JSON:
{
"key1" : "somevalue",
"key2" : "somevalue2",
"contacts" : {
"John Doe" : {
"position" : "CEO",
"phone" : "1234-5678-0",
"email" : "[email protected]"
},
"Elvis Presley" : {
"position" : "Singer",
"phone" : "0234-5678-0",
"email" : "[email protected]"
},
"Albert Einstein" : {
"position" : "Thinker",
"phone" : "0000-8888-0",
"email" : "[email protected]"
}
}
結果:
+-----------------+----------+-------------+---------------------+
| NAME | POSITION | PHONE | EMAIL |
+-----------------+----------+-------------+---------------------+
| John Doe | CEO | 1234-5678-0 | [email protected] |
+-----------------+----------+-------------+---------------------+
| Elvis Presley | Singer | 0234-5678-0 | [email protected] |
+-----------------+----------+-------------+---------------------+
| Albert Einstein | Thinker | 0000-8888-0 | [email protected] |
+-----------------+----------+-------------+---------------------+
如果是IS JSON,它是一個字符串,你如何解析它?如果它只是一個JavaScript對象,那麼這是另一回事。請澄清。 –