的onclick提交檢查PHP

Question

我有以下的PHP腳本，但它似乎爲會話始終檢查，因此回聲出「請輸入正確的密碼之前，用戶甚至已經進入了一個碼。

我想。在之前的代碼實際上火災確實爲會話和形式的崗位檢查click事件怎麼可以這樣在PHP做

這裏是我的代碼：？

<?php 

session_start(); 
    if (md5($_POST['norobot']) == $_SESSION['randomnr2']) 
    { 
     // here you place code to be executed if the captcha test passes 
      echo "Code correct - email should send now"; 

} 

else { 
     // here you place code to be executed if the captcha test fails 
      echo "Code incorect please try again"; 
    } 

?> 

我的提交按鈕看起來像這樣：

<input type="submit" id="submit_btn" class="button" value="Submit" /> 

Answer 1

<?php 
    session_start(); 
    if (isset($_POST['norobot'])) { 
     if (md5($_POST['norobot']) == $_SESSION['randomnr2']) { 
      // here you place code to be executed if the captcha test passes 
      echo "Code correct - email should send now"; 
     } 
     else { 
      // here you place code to be executed if the captcha test fails 
      echo "Code incorect please try again"; 
     } 
    } 
?> 

Answer 2

如果你想檢查會話變量設置，並具有非空值，你可以這樣做：

if(isset($_SESSION['THECODE']) && $_SESSION['THECODE']!='') 
{ 
    // THECODE is set to something 
} 

=========== =

UPDATE，因爲您添加代碼：

<?php 

session_start(); 
if(isset($_POST['norobot']) && isset($_SESSION['randonnr2'])) 
{ 
    if (md5($_POST['norobot']) == $_SESSION['randomnr2']) 
    { 
    echo "Code correct - email should send now"; 
    } 
    else 
    { 
    echo "Code incorect please try again"; 
    } 
} 

?> 

Answer 3

爲什麼不這樣做？檢查用戶是否提交了任何內容，如果不是，則不執行代碼。

<?php 

session_start(); 

if(isset($_POST)) 
    if (md5($_POST['norobot']) == $_SESSION['randomnr2']) 
    { 
     // here you place code to be executed if the captcha test passes 
      echo "Code correct - email should send now"; 

} 

else { 
     // here you place code to be executed if the captcha test fails 
      echo "Code incorect please try again"; 
    } 
} 

?>