Question

我正在嘗試使用PDO更新我的postgres數據庫中的一行。

表單不會將變量發送到處理程序文件。

我不確定問題出在哪裏，我一直在爲此奮鬥了幾天。

形式

//$maxContent is set and available 
//$context_number is set and available 
    echo"<form method='post' action='updateSpatialPhoto_handler.php'>"; 

    $query3 = $conn->prepare("SELECT * FROM excavation.contexts_spatial_photographs 
     WHERE contexts_spatial.area_easting = {$_SESSION['area_easting']} 
     AND contexts_spatial.area_northing = {$_SESSION['area_northing']} 
     AND contexts_spatial.context_number = {$_SESSION['context_number']}"); 

//contexts_spatial_photographs 
    $query3->execute(); 

while($r = $query3->fetch(PDO::FETCH_OBJ)) 
    { 
    // for each needed 
     echo"<input type='hidden' name='photograph_date' value='".$r->photograph_date."'>"; 
     echo"<input type='hidden' name='photograph_number' value='".$r->photograph_number."'>"; 
     echo"<input type='hidden' name='primary_shot' value='".$r->primary_shot."'>"; 

     echo"<input type='hidden' name='maxContext' value='", $maxContext,"'>"; 
    }; 

    echo"<input type='submit' value='Update Spatial Photo'>"; 
echo "</form>"; 

處理

<?php 
    session_start(); 

    // 
    include 'connect/connect.php'; 
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 

    if (!isset($_SESSION['photograph_date'])) {$_SESSION['photograph_date'] = $_POST['photograph_date'];} 
    if (!isset($_SESSION['photograph_number'])) {$_SESSION['photograph_number'] = $_POST['photograph_number'];} 
    if (!isset($_SESSION['primary_shot'])) {$_SESSION['primary_shot'] = $_POST['primary_shot'];} 
    if (!isset($_SESSION['maxContext'])) {$_SESSION['maxContext'] = $_POST['maxContext'];} 

    if (isset($_SESSION['photograph_date'])) {$_SESSION['photograph_date'] = $_POST['photograph_date'];} 
    if (isset($_SESSION['photograph_number'])) {$_SESSION['photograph_number'] = $_POST['photograph_number'];} 
    if (isset($_SESSION['primary_shot'])) {$_SESSION['primary_shot'] = $_POST['primary_shot'];} 
    if (isset($_SESSION['maxContext'])) {$_SESSION['maxContext'] = $_POST['maxContext'];} 

    //echo "Photograph Date: "; echo $_SESSION['photograph_date']; echo "<br />"; 
    //echo "Photograph Number: "; echo $_SESSION['photograph_number']; echo "<br />"; 
    //echo "Primary Shot: "; echo $_SESSION['primary_shot']; echo "<br />"; 

try { 
    $sql3 = "UPDATE excavation.contexts_spatial_photographs SET 
     context_number = :context_number 
     WHERE contexts_spatial_photographs.area_easting = $area_easting 
     AND contexts_spatial_photographs.area_northing = $area_northing 
     AND contexts_spatial_photographs.context_number = $context_number"; 

    $stmt2 = $conn->prepare($sql3); 

    // prepare sql and bind parameters 
    $stmt2->bindParam(':context_number', $maxContext, PDO::PARAM_INT); 
    $stmt2->execute(); 

    echo "Record updated successfully in contexts spatial photographs<br />"; 

    } 
catch(PDOException $e) 
    { 
    echo "Error: " . $e->getMessage(); 
    } 

?> 

Answer 1

在處理程序，您使用線條狀頂部...

if (isset($_SESSION['maxContext'])) {$_SESSION['maxContext'] = $_POST['maxContext'];} 

這些在會話變量中的值， ，這很好。 但在你的SQL -

AND contexts_spatial_photographs.context_number = $maxContext"; 

$ maxContext似乎並沒有在任何地方設置。這可能是一樣的會話變量，所以你需要

$maxContext = $_SESSION['maxContext']; 

或

AND contexts_spatial_photographs.context_number = $_SESSION['maxContext']"; 

但如果你使用bindParam與他們的話會更好，你:context_number使用同樣的方式。