重組的xml文檔

Question

這裏是我的XML文檔的結構，

<worldpatentdata> 
    <patent-family> 
     <exchange-documents>......</exchange-documents> 
     <exchange-documents>......</exchange-documents> 
     <exchange-documents>......</exchange-documents> 
     <familymember>.....</familymember> 
     <exchange-documents>......</exchange-documents> 
     <exchange-documents>......</exchange-documents> 
     <familymember>.....</familymember> 
     <exchange-documents>......</exchange-documents> 
     <exchange-documents>......</exchange-documents> 
     <familymember>.....</familymember> 
    </patent-family> 
</worldpatentdata> 

在上面的XML結構，所有的<exchange-documents>元素被發現是<patent-family>元素的子節點。 我想這些<exchange-documents>元素作爲​​3210元素的childnode，使XML具有以下結構，

<worldpatentdata> 
    <patent-family> 
     <familymember>..... 
      <exchange-documents>......</exchange-documents> 
      <exchange-documents>......</exchange-documents> 
      <exchange-documents>......</exchange-documents> 
     </familymember> 
     <familymember>..... 
      <exchange-documents>......</exchange-documents> 
      <exchange-documents>......</exchange-documents> 
     </familymember> 
     <familymember>..... 
      <exchange-documents>......</exchange-documents> 
      <exchange-documents>......</exchange-documents> 
     </familymember> 
    </patent-family> 
</worldpatentdata> 

任何人可以幫助我在這？ 謝謝

Answer 1

通過DOM對<patent-family>的孩子進行迭代，記住你遇到的每一個<exchange-documents>。每當你看到一個<familymember>，移動它下面的記憶元素。

Answer 2

在我頭頂上方，一個方式可以是：

1. 使用XDocument加載XML，並創建一個tempXDocument。
2. foreach (XElement...通過元素和添加到其是<exchange-documents>
3. 在tempXDocument添加<familymember>當<familymember>被發現的XmlNodeList物品;並將XmlNodeList添加到tempXDocument。
4. 保存tempXDocument。