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我使用這個代碼peice的嘗試,並獲得所有最新的鳴叫我的網站上打印,但它的返回自己被未經過身份驗證錯誤。我在Dev部分創建了一個應用程序,並獲取我的使用者和OAuth密鑰,並將它們添加到代碼中的正確位置。Twitter的API PHP獲取最新的鳴叫沒有認證
<?php
function buildBaseString($baseURI, $method, $params) {
$r = array();
ksort($params);
foreach($params as $key=>$value){
$r[] = "$key=" . rawurlencode($value);
}
return $method."&" . rawurlencode($baseURI) . '&' . rawurlencode(implode('&', $r));
}
function buildAuthorizationHeader($oauth) {
$r = 'Authorization: OAuth ';
$values = array();
foreach($oauth as $key=>$value)
$values[] = "$key=\"" . rawurlencode($value) . "\"";
$r .= implode(', ', $values);
return $r;
}
$url = "https://api.twitter.com/1.1/statuses/user_timeline.json?screen_name=jameskrawczyk";
$oauth_access_token = "SECURITY";
$oauth_access_token_secret = "SECURITY";
$consumer_key = "SECURITY";
$consumer_secret = "SECURITY";
$oauth = array('oauth_consumer_key' => $consumer_key,
'oauth_nonce' => time(),
'oauth_signature_method' => 'HMAC-SHA1',
'oauth_token' => $oauth_access_token,
'oauth_timestamp' => time(),
'oauth_version' => '1.0');
$base_info = buildBaseString($url, 'GET', $oauth);
$composite_key = rawurlencode($consumer_secret) . '&' . rawurlencode($oauth_access_token_secret);
$oauth_signature = base64_encode(hash_hmac('sha1', $base_info, $composite_key, true));
$oauth['oauth_signature'] = $oauth_signature;
$header = array(buildAuthorizationHeader($oauth), 'Expect:');
$options = array(CURLOPT_HTTPHEADER => $header,
//CURLOPT_POSTFIELDS => $postfields,
CURLOPT_HEADER => false,
CURLOPT_URL => $url,
CURLOPT_RETURNTRANSFER => true,
CURLOPT_SSL_VERIFYPEER => false);
$feed = curl_init();
curl_setopt_array($feed, $options);
$json = curl_exec($feed);
curl_close($feed);
$twitter_data = json_decode($json, true);
foreach ($twitter_data as $elem)
{
print_r($elem);
echo '<br>';
}
返回錯誤頁面上
Array ([0] => Array ([message] => Could not authenticate you [code] => 32))
下載它根據自己的API 1.1簡介您仍然可以使用它,它只是不是首選。他們甚至舉例說明如何使用它 – jskrwyk
請投票給我的答覆我不再允許由於投票而提問 –