計數並刪除重複數組

Question

我想計數並刪除重複數組。爲了重複，整個數組將具有與另一個的鍵和值的匹配。

Array 
(
    [0] => Array 
     (
      [name] => Superman 
      [time] => 60 
     ) 

    [1] => Array 
     (
      [name] => Superman 
      [time] => 60 
     ) 

    [2] => Array 
     (
      [name] => Superman 
      [time] => 50 
     ) 

    [3] => Array 
     (
      [name] => Superman 
      [time] => 40 
     ) 

    [4] => Array 
     (
      [name] => Superman 
      [time] => 50 
     ) 

    [5] => Array 
     (
      [name] => Superman 
      [time] => 60 
     ) 

) 

分爲：

Array 
(
    [0] => Array 
     (
      [name] => Superman 
      [time] => 60 
      [count] => 3 
     ) 

    [1] => Array 
     (
      [name] => Superman 
      [time] => 50 
      [count] => 2 
     ) 

    [2] => Array 
     (
      [name] => Superman 
      [time] => 40 
     ) 

) 

我遇到this answer that can remove the duplicates，但我掙扎，看我怎麼可能指望他們。

$input = array_map("unserialize", array_unique(array_map("serialize", $input))); 

Answer 1

不作爲因爲我想，但它可以完成工作：

function unserialize_unique_count($input, $k = 'count') { 
    $a = []; 
    foreach ($input as $d) { 
     $s = serialize($d); 
     $a[$s] = (isset($a[$s]) ? ($a[$s] + 1) : 1); 
    } 
    foreach ($a as $s => $c) { 
     $a[$s] = unserialize($s) + [ $k => $c ]; 
    } 
    return array_values($a); 
} 

$grouped_with_count = unserialize_unique_count($input); 

工作原理：第一個循環序列化並計數。第二個獨特的合併。上）。

如何使用：將您的多維數組作爲參數＃1傳遞。通過一個附加密鑰「count」來保存計數，從而帶給你獨特的體驗。如果您希望count鍵不是「count」，請傳遞函數第二個參數。

Answer 2

在這種情況下，您也可以使用array_count_values。例如：

$values = array(
    array('name' => 'Superman', 'time' => 60), 
    array('name' => 'Superman', 'time' => 60), 
    array('name' => 'Superman', 'time' => 50), 
    array('name' => 'Superman', 'time' => 40), 
    array('name' => 'Superman', 'time' => 50), 
    array('name' => 'Superman', 'time' => 60), 
); 

// map out into string then unique them 
$uniques = array_map("unserialize", array_unique(array_map("serialize", $values))); 
$count = array_count_values(array_map("serialize", $values)); // map out the arrays then get the counts 

// then to merge the count 
foreach($uniques as &$batch) { 
    foreach($count as $array => $v) { 
     if(unserialize($array) == $batch) { // if this particular key count is equal to this unique array, then push the count 
      $batch['count'] = $v; 
     } 
    } 
} 

echo '<pre>'; 
print_r($uniques); 

Sample Output

Answer 3

1. 獲取陣列及其價值
2. 就paypal_address唯一鍵
3. 使用唯一的密鑰創建臨時數組
4. 商店都在各自的唯一鍵值temp array

5. 我使用時間作爲唯一鍵。

   $tmpArr = Array(); 
   $cnt = sizeof($arr); 
   for($i=0;$i<$cnt;$i++){ 
        $time = $arr[$i]['time']; 
        if(!is_array($tmpArr[$time])){ 
          $tmpArr[$time] = Array(); 
          $tmpArr[$time]['count'] = 0; 
        } 
        $tmpArr[$time]['time'] = $arr[$i]['time']; 
        $tmpArr[$time]['name'] = $arr[$i]['name']; 
        $tmpArr[$time]['count'] = $tmpArr[$time]['count'] + 1; 
   
   } 
   print_r($tmpArr); 
   

注：根據您的要求製作的代碼更改

Answer 4

快速和骯髒的，但你得到正是你要求的數據結構：

$data = array(
    array("name" => "Superman", "time" => 60), 
    array("name" => "Superman", "time" => 60), 
    array("name" => "Superman", "time" => 50), 
    array("name" => "Superman", "time" => 40), 
    array("name" => "Superman", "time" => 50), 
    array("name" => "Superman", "time" => 60), 
); 

// count the occurrences 
$occurrences = array(); 
for ($i = 0, $l = count($data); $i < $l; $i++) { 
    $serialized = serialize($data[$i]); 
    if (!isset($occurrences[$serialized])) { 
     $occurrences[$serialized] = 1; 
    } 
    else { 
     $occurrences[$serialized] = $occurrences[$serialized] + 1; 
    } 
} 

// get the wanted structure 
$uniques = array(); 
foreach ($occurrences as $serialized => $count) { 
    $unserialized = unserialize($serialized); 
    if ($count > 1) { 
     $unserialized['count'] = $count; 
    } 
    $uniques[] = $unserialized; 
} 

print_r($uniques);