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用日曆回覆所有月份

2011-04-04 113 views
0

我正在使用下面的代碼來回顯當前月份。我怎樣才能提高它，這樣是顯示所有與名稱和天數和日期的月份..用日曆回覆所有月份

代碼：一個函數中

<?php 
$today = getdate(); 
$firstDay = getdate(mktime(0,0,0,$today['mon'],1,$today['year'])); 
$lastDay = getdate(mktime(0,0,0,$today['mon']+1,0,$today['year'])); 


?> 

<?php 

echo '<table>'; 
echo ' <tr><th colspan="7">'.$today['month']." - ".$today['year']."</th></tr>"; 
echo '<tr class="days">'; 
echo ' <td>Mo</td><td>Tu</td><td>We</td><td>Th</td>'; 
echo ' <td>Fr</td><td>Sa</td><td>Su</td></tr>'; 
?> 

<?php 
echo '<tr>'; 
for($i=1;$i<$firstDay['wday'];$i++){ 
    echo '<td>&nbsp;</td>'; 
} 
$actday = 0; 
for($i=$firstDay['wday'];$i<=7;$i++){ 
    $actday++; 
    echo "<td>$actday</td>"; 
} 
echo '</tr>'; 
?> 

<?php 
$fullWeeks = floor(($lastDay['mday']-$actday)/7); 

for ($i=0;$i<$fullWeeks;$i++){ 
    echo '<tr>'; 
    for ($j=0;$j<7;$j++){ 
     $actday++; 
     echo "<td>$actday</td>"; 
    } 
    echo '</tr>'; 
    } 
    ?> 

    <?php 
    if ($actday < $lastDay['mday']){ 
    echo '<tr>'; 

    for ($i=0; $i<7;$i++){ 
     $actday++; 
     if ($actday <= $lastDay['mday']){ 
      echo "<td>$actday</td>"; 
     } 
     else { 
      echo '<td>&nbsp;</td>'; 
     } 
    } 

    echo '</tr>'; 
} 
?>

來源

2011-04-04 AAA

+1

http://php.net/date或者你有什麼具體問題？ – fabrik 2011-04-04 08:46:47

+0

沒問題。這段代碼很好，但我想要所有的月份，而不僅僅是當前的。 – AAA 2011-04-04 08:49:31

回答

8

試試這個：

function getDates($year) 
{ 
    $dates = array(); 

    for($i = 1; $i <= 366; $i++){ 
     $month = date('m', mktime(0,0,0,1,$i,$year)); 
     $wk = date('W', mktime(0,0,0,1,$i,$year)); 
     $wkDay = date('D', mktime(0,0,0,1,$i,$year)); 
     $day = date('d', mktime(0,0,0,1,$i,$year)); 

     $dates[$month][$wk][$day] = $wkDay; 
    } 

    return $dates; 
}

它將返回個月 - >周 - > day->你傳遞給函數的一年平日的數組。希望遍歷數組來打印所有內容應該很容易。確保你可以做出很多調整，但這只是一個開始。例如

我也會嘗試遠離使用echo打印出html，例如，而不是;

echo '<tr>'; 
for($i=1;$i<$firstDay['wday'];$i++){ 
    echo '<td>&nbsp;</td>'; 
}

做;

<tr>; 
<?php for($i=1;$i<$firstDay['wday'];$i++){ ?> 
    <td><?php echo $var; ?></td> 
<?php } ?>

它使我的代碼更具可讀性。

編輯：只是想我應該包括使用情況的例子還有，如下：

<?php $dates = getDates(2011); 

$weekdays = array('Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'); ?> 
<?php foreach($dates as $month => $weeks) { ?> 
<table> 
    <tr> 
     <th><?php echo implode('</th><th>', $weekdays); ?></th> 
    </tr> 
    <?php foreach($weeks as $week => $days){ ?> 
    <tr> 
     <?php foreach($weekdays as $day){ ?> 
     <td> 
      <?php echo isset($days[$day]) ? $days[$day] : '&nbsp'; ?> 
     </td>    
     <?php } ?> 
    </tr> 
    <?php } ?> 
</table> 
<?php } ?>

，讓你的輸出：

enter image description here

來源

2011-04-04 10:22:35 Daz

+1

只是爲了防止其他人使用它，爲了使您的示例代碼工作，您需要設置'$日期[$月] [ $ wk] [$ wkDay] = $ day;'而不是'$ dates [$ month] [$ wk] [$ day] = $ wkDay;'在你的函數中。 – javiervd 2014-10-11 21:41:59

1

總結當前的代碼，然後將參數傳遞給它與你的期望日期。

來源

2011-04-04 08:50:47 fabrik

+0

我只想回應所有的月份......我找不到能做的事情，我看到與getdate相關的東西... – AAA 2011-04-04 08:57:59

+0

@AAA你能告訴我你的具體問題是什麼？ – fabrik 2011-04-04 09:08:01

+0

問題是當前的代碼顯示當前月份。我想做一個在線日曆，所以我想在網站上的所有當前和未來幾個月/年.. – AAA 2011-04-04 17:13:34

5

您可以使用此功能將整個年份轉換爲陣列

function year2array($year) { 
    $res = $year >= 1970; 
    if ($res) { 
     // this line gets and sets same timezone, don't ask why :) 
     date_default_timezone_set(date_default_timezone_get()); 

     $dt = strtotime("-1 day", strtotime("$year-01-01 00:00:00")); 
     $res = array(); 
     $week = array_fill(1, 7, false); 
     $last_month = 1; 
     $w = 1; 
     do { 
     $dt = strtotime('+1 day', $dt); 
     $dta = getdate($dt); 
     $wday = $dta['wday'] == 0 ? 7 : $dta['wday']; 
     if (($dta['mon'] != $last_month) || ($wday == 1)) { 
      if ($week[1] || $week[7]) $res[$last_month][] = $week; 
      $week = array_fill(1, 7, false); 
      $last_month = $dta['mon']; 
      } 
     $week[$wday] = $dta['mday']; 
     } 
     while ($dta['year'] == $year); 
     } 
    return $res; 
    }

叫它像所以

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       ) 

     ) 

)

，現在可以很容易地創建月表則需要使用這樣的事情

每月： 

print_r(year2array(2011));

你會在源看到這（個月 - >周 - >天） 

function month2table($month, $calendar_array) { 
    $ca = 'align="center"'; 
    $res = "<table cellpadding=\"2\" cellspacing=\"1\" style=\"border:solid 1px #000000;font-family:tahoma;font-size:12px;background-color:#ababab\"><tr><td $ca>Mo</td><td $ca>Tu</td><td $ca>We</td><td $ca>Th</td><td $ca>Fr</td><td $ca>Sa</td><td $ca>Su</td></tr>"; 
    foreach ($calendar_array[$month] as $month=>$week) { 
     $res .= '<tr>'; 
     foreach ($week as $day) { 
     $res .= '<td align="right" width="20" bgcolor="#ffffff">' . ($day ? $day : '&nbsp;') . '</td>'; 
     } 
     $res .= '</tr>'; 
     } 
    $res .= '</table>'; 
    return $res; 
    }

使用這些功能就像

$calarr = year2array(2011); 
    echo month2table(1, $calarr); // January 
    echo month2table(2, $calarr); // February 
    ... 
    echo month2table(12, $calarr); // December

..或在for循環中放入月份。

因此......例如，爲2011年1月在瀏覽器中你會看到這個

enter image description here

希望這有助於。

來源

2011-04-04 11:53:20 Wh1T3h4Ck5

+0

這不起作用 – 2013-12-10 14:19:06

+0

@JohnSmith剛剛檢查過它，它的工作原理。我不知道你試過了什麼，但可能你做錯了什麼。請注意，它已經有2.5年曆史了，自從最初發布以來，PHP已經更新了很多次，也許你正面臨一些兼容性問題，但從這一點來說，我不能說你的問題出了什麼問題。它適用於我的在線和本地工作（使用兩臺不同的服務器進行測試）。 – Wh1T3h4Ck5 2013-12-10 18:03:34

+0

多數民衆贊成可能，我有一個v.uptodate PHP現在我在這裏 – 2013-12-13 21:55:27

0 
$daysArr = array('Mon','Tue','Wed','Thu','Fri','Sat','Sun'); 
$monthtotdays= cal_days_in_month(CAL_GREGORIAN,date('m'),date("Y")); 
$currdays=jddayofweek (cal_to_jd(CAL_GREGORIAN, date('m'),1, date("Y")) , 2); 
$currdaysval = 0; 
echo "<table border=1px>"; 
echo "<tr>"; 
for($d=0;$d<=6;$d++){ 
echo "<td>". $daysArr[$d]."</td>"; 
if($daysArr[$d]==$currdays) $currdaysval = $d; 
} 

echo "</tr>"; 
echo "<tr>"; 
if($currdaysval > 0){ 
echo '<td colspan="'.$currdaysval.'">&nbsp;</td>'; 
} 
for($i=1;$i<=$monthtotdays;$i++){ 
echo "<td>".$i."</td>"; 
if(($i+$currdaysval)%7 <= 0){ 
echo "</tr><tr>"; 
} 
} 
echo "</tr></table>"

來源

2014-05-05 11:53:25 sheik

1

最好的答案有一個不準確的地方！如果年份爲閏年，則應在一個週期之前添加一個條件，否則在第一個月的第一天的輸出產生問題see screenshot。

的必要條件：date("L", mktime(0,0,0, 7,7, $year)) ? $days = 366 : $days = 365; （如果今年是閏年則反週期= 366其他365）

來源

2017-10-13 17:46:41

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