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我有名稱的表格,當我點擊名稱時,我需要打開模式並將名稱點擊在那裏。我如何做到這一點?在此先感謝從模態頁面獲得價值
report.php
按鈕:
<a href='#ReportModal' data-id='1' data-toggle='modal'>Open</a></td>
模式:
<div id="ReportModal" class="modal" role="dialog" data-backdrop="static" data-keyboard="false">
<div class="modal-dialog">
<!-- Modal content-->
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">asd</h4>
</div>
<div class="modal-body">
//HOW TO PRINT HERE?
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
腳本
<script>
$(document).ready(function() {
$(document).on("click",".get-data"function(){
var val = $(this).attr("data-id");
$.ajax({
url: "../dist/scripts/report.userinfo.php",
type: "POST",
dataType: "HTML",
async: false,
success: function(data) {
$('.modal-body').html(data);
}
});
});
});
</script>
report.userinfo.php
<?php
include($_SERVER['DOCUMENT_ROOT']."/dist/config.php");
$id = $_POST['id'];
$query = $db->query ("select Name from _reports where ID = '$id' ") or die($db->error());
$rows= $query->fetch_array();
echo $rows['Name'];
?>
請與我們分享您的JS代碼,所以我們可以看到你已經嘗試了什麼,以及我們如何可以幫助你。 –
@小時 - 你不能這樣做。 PHP是服務器端,因此當您單擊頁面本身時,PHP就已經很長時間了。 – DocRattie
@DocRattie我加了腳本,請幫忙) –