我設法做到這一點的唯一方法是通過渲染到一個單獨的元素和複製元素。
例如:
<form id="my-form">
<!-- My controls: -->
<label for="foo">Foo</label>
<input id="foo">
<label for="bar">Bar</label>
<input id="bar">
<!-- I want the schema-based controls to go into this div. -->
<div class="schema-control-container"></div>
</form>
中的JavaScript(和jQuery):
var $myForm = $('#my-form');
var $schemaControlContainer = $myForm.find('.schema-control-container');
var mySchema = JSON.parse(mySchemaJson);
var $scratchpad = $('<div id="alpacaScratchpad"></div>').hide().
insertAfter($myForm);
function postRender (control) {
// I actually have multiple forms, so I need to make sure the IDs are unique.
$scratchpad.find('.alpaca-control').each(function (i, alpacaControl) {
alpacaControl.id = $myForm.attr('id') + '-' + alpacaControl.id;
});
$scratchpad.find('.alpaca-control-label').each(
function (i, alpacaControlLabel) {
alpacaControlLabel.htmlFor = $myForm.attr('id') + '-' +
alpacaControlLabel.htmlFor;
});
// Select elements we want to copy. Note that I haven't tried this with any
// particularly complicated JSON schemata, so this may be naïve.
var $goodies = $scratchpad.find('.alpaca-control,.alpaca-control-label');
// Optional: mark schema controls as such, and allow autocompletion.
$goodies.filter('.alpaca-control').addClass('my-schema-datum').
attr('autocomplete', null);
// Remove Alpaca classes and Bootstrap crap. (I hate Bootstrap, but the 'web'
// version of Alpaca doesn't seem to work right now. TODO: Update after
// https://github.com/gitana/alpaca/issues/507 is fixed.)
$goodies.removeClass('alpaca-control').removeClass('alpaca-control-label').
removeClass('form-control').removeClass('control-label');
// Move the goodies to the schema control container, in the form.
$schemaControlContainer.append($goodies);
// Clean up the clutter we don't need.
$scratchpad.empty();
}
// Have Alpaca render the schema into the scratchpad, and then run the function
// we just defined.
$scratchpad.alpaca({ schema: mySchema, postRender: postRender });
我希望能找到一個羊駝選項,以防止需要做這一切,但似乎並不成爲一個。