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序列化KSOAP問題,我在我的應用程序中使用SOAP服務,當我打電話SOAP服務它拋出一些不能序列化問題:不能在Android的
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
SoapObject authentication = new SoapObject(NAMESPACE,"authentication");
PropertyInfo usrid =new PropertyInfo();
usrid.setName("LoginID");
usrid.setValue("sting");
usrid.setType(String.class);
authentication.addProperty(usrid);
PropertyInfo pass =new PropertyInfo();
pass.setName("Password");
pass.setValue("string");
pass.setType(String.class);
authentication.addProperty(pass);
request.addSoapObject(authentication);
PropertyInfo nos =new PropertyInfo();
no.setName("No");
no.setValue(no);
no.setType(String.class);
//authentication.addProperty(no);
request.addProperty("Str", nos);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);
envelope.dotNet=true;
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
try
{
androidHttpTransport.call(SOAP_ACTION,envelope);
Object result=(Object)envelope.getResponse(); --------->Here i am getting nullpointer.
Log.i("myApp",result.toString());
System.out.println("subbu="+result.toString());
}
我的請求結構是:
<authentication>
<LoginID>string</LoginID>
<Password>string</Password>
</authentication>
<No>string</No>
我收到錯誤消息:
java.lang.RuntimeException: Cannot serialize:No:
Hi andreapier ...實際上,no是一個字符串String no = getIntent()。getStringExtra(「no」);我從previos屏幕獲得。 – subburaj
看一個代碼...你正在用我的答案中指出的PropertyInfo no = new PropertyInfo()覆蓋字符串no。 – andreapier
oh andreapier..sory現在我編輯了代碼..現在我解決了序列化問題,現在我收到錯誤SoapFault - faultcode:'soap:Server'faultstring:'System.Web.Services.Protocols.SoapException:Server was無法處理請求。 ---> System.NullReferenceException:未將對象引用設置爲對象的實例。 – subburaj