PHP：經過一些算術操作合併兩個陣列

Question

我需要請你的幫助，因爲我不知道如何從這個隧道退出。

我有這個有點數組（它們是地方）：

$places = 
Array 
(
    [0] => Array 
     (
      [id] => 3 
      [route] => Via dei Gelsi 
      [street_number] => 1 
      [postal_code] => 00171 
      [administrative_area_level_3] => Roma 
      [administrative_area_level_2_short] => RM 
     ) 

    [1] => Array 
     (
      [id] => 6 
      [route] => Via Ugo Bartolomei 
      [street_number] => 6 
      [postal_code] => 00136 
      [administrative_area_level_3] => Roma 
      [administrative_area_level_2_short] => RM 
     ) 

    [2] => Array 
     (
      [id] => 8 
      [route] => Via di San Giovanni in Laterano 
      [street_number] => 20 
      [postal_code] => 00184 
      [administrative_area_level_3] => Roma 
      [administrative_area_level_2_short] => RM 
     ) 

) 

而且每個地方都有0,1或更多的評論：

$comments = 
Array 
(
[0] => Array 
    (
     [0] => Array 
      (
       [id] => 4 
       [id_place] => 3 
       [id_user] => 1 
       [a] => 1 
       [b] => 3 
       [c] => 2 
       [d] => 4 
      ) 

     [1] => Array 
      (
       [id] => 11 
       [id_place] => 3 
       [id_user] => 1 
       [a] => 5 
       [b] => 5 
       [c] => 4 
       [d] => 3 
      ) 

    ) 

[1] => Array 
    (
     [0] => Array 
      (
       [id] => 5 
       [id_place] => 6 
       [id_user] => 1 
       [a] => 5 
       [b] => 4 
       [c] => 5 
       [d] => 4 
      ) 

     [1] => Array 
      (
       [id] => 6 
       [id_place] => 6 
       [id_user] => 1 
       [a] => 1 
       [b] => 1 
       [c] => 1 
       [d] => 1 
      ) 

     [2] => Array 
      (
       [id] => 7 
       [id_place] => 6 
       [id_user] => 1 
       [a] => 1 
       [b] => 4 
       [c] => 3 
       [d] => 2 
      ) 



    ) 

[2] => Array 
    (
    ) 

[3] => Array 
    (
     [0] => Array 
      (
       [id] => 13 
       [id_place] => 9 
       [id_user] => 1 
       [a] => 1 
       [b] => 1 
       [c] => 1 
       [d] => 1 
      ) 

    ) 

[4] => Array 
    (
    ) 
) 

我需要執行一些還挺操作，以僞碼爲例：

foreach ($comments as $key=>$value) 
{ 
     $how_many_comments = count how many comments have same $value['id_place'] 
     // for $comments[0] the result is 2 
     // pick every a, b, c, d, multiplicate for 2, 2, 3 and 4 and sign result 
     $a = $value['a']*2; 
     $b = $value['b']*2; 
     $c = $value['c']*3; 
     $d = $value['d']*4; 
     // and so on 
     $sum_partial = ($a+$b+$c+$d)/11; 
     $sum = $sum+$partial_sum; 
     $total = round($sum/$how_many_comments),1) 

     // set in first array ($place) $total (calculated as 3.3) where $comments['id_place'] == $result['id'] 
} 

因此，最終數組$ place需要類似於：

Array 
(
    [0] => Array 
     (
      [id] => 3 
      [route] => Via dei Gelsi 
      [street_number] => 1 
      [postal_code] => 00171 
      [administrative_area_level_3] => Roma 
      [administrative_area_level_2_short] => RM 
      [total] = 3.3 
      [num_comments] = 2 
     ) 
) 

請......非常非常感謝！

Answer 1

剛剛解決。

 $quanti_commenti = count($comments); 
     if ($quanti_commenti>0) 
     { 
      foreach ($comments as $key=>$value) 
      { 
       $result[$i]['quanti_commenti'] = $quanti_commenti; 
       $a = $value['a']*2; 
       // 
       $somma_parziale = ($a+$b+$c+$d)/11; 
       $somma = $somma+$somma_parziale; 
       $total = round(($somma/$quanti_commenti),1); 
       $result[$i]['total'] = $total; 
      } 
      $somma = 0; 
      $total = 0; 
     } 
     $i++;