獲取PHP中的文件鏈接

Question

我們有一個VOIP服務器，用於存儲通話記錄的wav文件。我的意圖是將一個PHP文件放在一起，我可以在文件的URL中傳遞calldate和uniqueid值（因爲服務器將這些文件存儲爲文件名的一部分）以檢索文件的鏈接。

「解析錯誤：語法錯誤，在/var/www/html/maint/helloworld.php意想不到的$結束第42行」

但是，試圖這樣做時，我得到以下錯誤

<?php 

function getRecordingLink($callDate, $uniqueId){ 

$callDate_arr = explode(' ', $callDate); 

$removeChar = array('-',':'); 
foreach($callDate_arr as $value){ 
    $callDate_arr_adj[] = str_replace($removeChar,'',$value); 
} 

$audioDirectory_array = array(); 
if ($handle = opendir('/var/spool/asterisk/monitor/')) { 
    while (false != ($file = readdir($handle))) { 
     if ($file != "." && $file != "..") { 
      $audioDirectory_array[] = $file; 
     } 
    } 
    closedir($handle); 
} 

foreach($audioDirectory_array as $key => $value){ 

    if (preg_match ("/".$uniqueId."/i", $value)) { 
     if(file_exists('/var/spool/asterisk/monitor/'.$value)){ 
      $wavFile = $value; 
      //return '<a href="/maint/modules/cdrreport/monitor/'.$wavFile.'" target="_blank">Recorded File</a>'; 
      return '/maint/cache/monitor/' . $wavFile; 
     } 
    }else{ 
     //return "Not Recorded"; 
    } 

getRecordingLink ('20110513','1305274000.2'); //sample calldate and uniqueid values for testing 

？>

下面是MySQL數據庫表從那裏我將拿起值的描述傳遞到這個網址calldate和uniqueid`

mysql> describe cdr 
    -> ; 
+-------------+--------------+------+-----+---------------------+-------+ 
| Field  | Type   | Null | Key | Default    | Extra | 
+-------------+--------------+------+-----+---------------------+-------+ 
| calldate | datetime  | NO |  | 0000-00-00 00:00:00 |  | 
| clid  | varchar(80) | NO |  |      |  | 
| src   | varchar(80) | NO |  |      |  | 
| dst   | varchar(80) | NO |  |      |  | 
| dcontext | varchar(80) | NO |  |      |  | 
| channel  | varchar(80) | NO |  |      |  | 
| dstchannel | varchar(80) | NO |  |      |  | 
| lastapp  | varchar(80) | NO |  |      |  | 
| lastdata | varchar(80) | NO |  |      |  | 
| duration | int(11)  | NO |  | 0     |  | 
| billsec  | int(11)  | NO |  | 0     |  | 
| disposition | varchar(45) | NO |  |      |  | 
| amaflags | int(11)  | NO |  | 0     |  | 
| accountcode | varchar(20) | NO |  |      |  | 
| uniqueid | varchar(32) | NO |  |      |  | 
| userfield | varchar(255) | NO |  |      |  | 
+-------------+--------------+------+-----+---------------------+-------+ 

Answer 1

右鍵，剛剛在這個:-P

你缺少兩個花括號從文件的底部上方getRecordingLink()另一個好辛苦的樣子：

function getRecordingLink($callDate, $uniqueId){ 

    $callDate_arr = explode(' ', $callDate); 

    $removeChar = array('-',':'); 
    foreach($callDate_arr as $value){ 
     $callDate_arr_adj[] = str_replace($removeChar,'',$value); 
    } 

    $audioDirectory_array = array(); 
    if ($handle = opendir('/var/spool/asterisk/monitor/')) { 
     while (false != ($file = readdir($handle))) { 
      if ($file != "." && $file != "..") { 
       $audioDirectory_array[] = $file; 
      } 
     } 
     closedir($handle); 
    } 

    foreach($audioDirectory_array as $key => $value){ 
     if (preg_match ("/".$uniqueId."/i", $value)) { 
      if(file_exists('/var/spool/asterisk/monitor/'.$value)){ 
       $wavFile = $value; 
       //return '<a href="/maint/modules/cdrreport/monitor/'.$wavFile.'" target="_blank">Recorded File</a>'; 
       return '/maint/cache/monitor/' . $wavFile; 
      } 
     }else{ 
      //return "Not Recorded"; 
     } 
    } 
} 
getRecordingLink ('20110513','1305274000.2'); 

我從here得到了錯誤是：

Parse error: syntax error, unexpected $end in /homepages/26/d94605010/htdocs/lz/writecodeonline.com/php/index.php(98): eval()'d code on line 32

該文件現在爲我解析，但我無法測試它實際上做了什麼。如果這不起作用，請在評論中遵循我的建議。