如何在序列化時添加ENTITY？

Question

問題

我可以修改我的POCO類，以便序列化時，它們包含所需的ENTITY S'在閱讀this from W3C和this answer to a similar question後，我意識到我的XML應該包含DOCTYPE如下，我只是不知道如何插入它。

<?xml version="1.0" encoding="utf-16"?> 
<!DOCTYPE documentElement[<!ENTITY NZ "NZ"><!ENTITY AU "AU">]> 
<ValuationTransaction xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="https://vx.valex.com.au/lixi/schema/1.3.5/ValuationTransaction.xsd" ProductionData="Yes"> 
    ... etc. 
</ValuationTransaction> 

我的串行化的代碼如下所示

public static string ToXmlString(this ValuationTransaction payloadPoco) 
{ 
    var stringwriter = new StringWriter(); 
    var serializer = new XmlSerializer(payloadPoco.GetType()); 
    serializer.Serialize(stringwriter, payloadPoco); 
    return stringwriter.ToString(); 
} 

背景

我使用的是XmlSerializer和StringWriter連載我的根類爲一個字符串，然後驗證使用XML字符串一個來自this post的XmlValidator。在驗證XML驗證器說...

引用未申報的實體，'NZ'。在管線37的位置24

...這是指該元素

<Country ISO3166="NZ">NEW ZEALAND</Country> 

的ISO3166屬性...的定義是：

[System.Xml.Serialization.XmlAttributeAttribute(DataType = "ENTITY")] 
public string ISO3166 
{ 
    get { return this.iSO3166Field; } 
    set { this.iSO3166Field = value; } 
} 

值的範圍我的目的僅限於NZ和AU。我可以添加DOCTYPE這樣，雖然很明顯，我寧願找一個更好的辦法：

var entitiesDtd = @"<!DOCTYPE documentElement[<!ENTITY NZ ""NZ""><!ENTITY AU ""AU"">]>" + Environment.NewLine; 
xmlString = xmlString.Insert(xmlString.IndexOf("<ValuationTransaction"), entitiesDtd); 

的XML根類（由xsd.exe產生並手動調整，以增加noNamespaceSchemaLocation）的定義是

[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.6.1055.0")] 
[System.SerializableAttribute()] 
[System.Diagnostics.DebuggerStepThroughAttribute()] 
[System.ComponentModel.DesignerCategoryAttribute("code")] 
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)] 
[System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)] 
public partial class ValuationTransaction 
{ 
    [XmlAttribute("noNamespaceSchemaLocation", Namespace = "http://www.w3.org/2001/XMLSchema-instance")] 
    public string noNamespaceSchemaLocation = "https://vx.valex.com.au/lixi/schema/1.3.5/ValuationTransaction.xsd"; 
    ... etc. 
} 

Answer 1

我改變了我的序列號，使它包含XmlWriter根據this answer。

XmlSerializer xsSubmit = new XmlSerializer(typeof(ValuationTransaction)); 
var subReq = payloadPoco; 
var xml = ""; 

using (var sww = new StringWriter()) 
{ 
    var writerSettings = new XmlWriterSettings(); 
    writerSettings.Indent = true; 

    using (XmlWriter writer = XmlWriter.Create(sww, writerSettings)) 
    { 
     writer.WriteDocType("documentElement", null, null, "<!ENTITY AU \"Australia\"><!ENTITY NZ \"New Zealand\">"); 
     xsSubmit.Serialize(writer, subReq); 
     xml = sww.ToString(); // Your XML 
     return xml; 
    } 
} 

Answer 2

您需要添加設置

  XmlWriterSettings settings = new XmlWriterSettings(); 
      settings.Indent = true; 
      XmlWriter writer = XmlWriter.Create(sww, settings);