嘗試使用PHP DOM替換節點文本而不更改子節點

Question

我正在嘗試使用dom對象來簡化詞彙表工具提示的實現。我需要做的是替換段落中的文本元素，而不是可能嵌入段落中的錨定標記。

$html = '<p>Replace this tag not this <a href="#">tag</a></p>'; 
$document = new DOMDocument(); 
$document->loadHTML($html); 
$document->preserveWhiteSpace = false; 
$document->validateOnParse = true; 

$nodes = $document->getElementByTagName("p"); 
foreach ($nodes as $node) { 
    $node->nodeValue = str_replace("tag","element",$node->nodeValue); 
} 
echo $document->saveHTML(); 

我得到：

'...<p>Replace this element not this element</p>...' 

我想：

'...<p>Replace this element not this <a href="#">tag</a></p>...' 

如何實現這使得只有父節點文本更改和子節點（標籤）是沒有改變？

Answer 1

試試這個：

$html = '<p>Replace this tag not this <a href="#">tag</a></p>'; 
$document = new DOMDocument(); 
$document->loadHTML($html); 
$document->preserveWhiteSpace = false; 
$document->validateOnParse = true; 

$nodes = $document->getElementsByTagName("p"); 

foreach ($nodes as $node) { 
    while($node->hasChildNodes()) { 
     $node = $node->childNodes->item(0); 
    } 
    $node->nodeValue = str_replace("tag","element",$node->nodeValue); 
} 
echo $document->saveHTML(); 

希望這有助於。

UPDATE 要回答@保羅在下面的評論的問題，您可以創建

$html = '<p>Replace this tag not this <a href="#">tag</a></p>'; 
$document = new DOMDocument(); 
$document->loadHTML($html); 
$document->preserveWhiteSpace = false; 
$document->validateOnParse = true; 

$nodes = $document->getElementsByTagName("p"); 

//create the element which should replace the text in the original string 
$elem = $document->createElement('dfn', 'tag'); 
$attr = $document->createAttribute('title'); 
$attr->value = 'element'; 
$elem->appendChild($attr); 

foreach ($nodes as $node) { 
    while($node->hasChildNodes()) { 
     $node = $node->childNodes->item(0); 
    } 
    //dump the new string here, which replaces the source string 
    $node->nodeValue = str_replace("tag",$document->saveHTML($elem),$node->nodeValue); 
} 
echo $document->saveHTML();