您好我想創建一個數據庫,然後根據從數據庫返回的值設置文本視圖值。我收到一個錯誤「SYNTAX ERROR(code1)」 這裏是我的代碼。錯誤,同時在Android上使用SQLITE
`package com.example.dbex;
import java.sql.SQLOutput;
import java.sql.SQLPermission;
import android.content.ContentValues;
import android.content.Context;
import android.database.Cursor;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteDatabase.CursorFactory;
import android.database.sqlite.SQLiteOpenHelper;
public class DBHandler extends SQLiteOpenHelper {
public static final int DATABASE_VERSION=1;
public static final String DATABASE_NAME="contactsmanager";
public static final String TABLE_CONTACTS="contacts";
public static final String KEY_ID="id";
public static final String KEY_NAME="name";
public static final String KEY_NUMBER="number";
public DBHandler(Context context) {
super(context,DATABASE_NAME, null, DATABASE_VERSION);
// TODO Auto-generated constructor stub
}
@Override
public void onCreate(SQLiteDatabase db) {
// TODO Auto-generated method stub
String CREATE_TABLE_CONTACTS="CREATE TABLE"+TABLE_CONTACTS+"("+KEY_ID+"INTEGER PRIMARY KEY,"+KEY_NAME+"TEXT,"+KEY_NUMBER+"TEXT"+")";
db.execSQL(CREATE_TABLE_CONTACTS);
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
// TODO Auto-generated method stub
db.execSQL("DROP TABLE IF EXISTS"+TABLE_CONTACTS);
onCreate(db);
}
public void addContact(Contacts contacts)
{
SQLiteDatabase db=this.getWritableDatabase();
ContentValues values=new ContentValues();
values.put(KEY_NAME, contacts.getname());
values.put(KEY_NUMBER, contacts.getnumber());
db.insert(TABLE_CONTACTS,null,values);
db.close();
}
public Contacts getContact(int id)
{
SQLiteDatabase db=this.getReadableDatabase();
Cursor c=db.query(TABLE_CONTACTS, new String[]{KEY_ID,KEY_NAME,KEY_NUMBER},KEY_ID+"=?",new String[]{String.valueOf(id)}, null, null, null, null);
if(c!=null)
{
c.moveToFirst();
}
Contacts contacts=new Contacts(Integer.parseInt(c.getString(0)),c.getString(1),c.getString(2));
return contacts;
}
public void deleteContact(Contacts contacts)
{
SQLiteDatabase db=this.getWritableDatabase();
db.delete(TABLE_CONTACTS, KEY_ID+"=?", new String[]{String.valueOf(contacts.getID())});
``db.close();
}
}
`
請幫我糾正一下我的錯誤。 感謝
謝謝。我已經這樣做了,但我現在得到一個錯誤,說有沒有這樣的列'id'和'數字'「? –
你需要更多的空間,它看起來像你正在創建一個名爲IDINTEGER – faffaffaff
列的表謝謝,我已經修復了由於空間造成的錯誤。但現在我在這一行上得到一個錯誤「光標索引超出界限」Contacts contacts = new Contacts(Integer.parseInt(c.getString(0)),c.getString(1),c.getString(2)) ;' –