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我嘗試這樣做：無法發送富文本郵件與Gmail API
var sendRequest = gapi.client.gmail.users.messages.send({
'userId': 'me',
'resource': {
'raw': window.btoa(email).replace(/\+/g, '-').replace(/\//g, '_')
}
});
而這一點，也：
var Base64={_keyStr:"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz/=",encode:function(e){var t="";var n,r,i,s,o,u,a;var f=0;e=Base64._utf8_encode(e);while(f<e.length){n=e.charCodeAt(f++);r=e.charCodeAt(f++);i=e.charCodeAt(f++);s=n>>2;o=(n&3)<<4|r>>4;u=(r&15)<<2|i>>6;a=i&63;if(isNaN(r)){u=a=64}else if(isNaN(i)){a=64}t=t+this._keyStr.charAt(s)+this._keyStr.charAt(o)+this._keyStr.charAt(u)+this._keyStr.charAt(a)}return t},decode:function(e){var t="";var n,r,i;var s,o,u,a;var f=0;e=e.replace(/[^A-Za-z0-9\+\/\=]/g,"");while(f<e.length){s=this._keyStr.indexOf(e.charAt(f++));o=this._keyStr.indexOf(e.charAt(f++));u=this._keyStr.indexOf(e.charAt(f++));a=this._keyStr.indexOf(e.charAt(f++));n=s<<2|o>>4;r=(o&15)<<4|u>>2;i=(u&3)<<6|a;t=t+String.fromCharCode(n);if(u!=64){t=t+String.fromCharCode(r)}if(a!=64){t=t+String.fromCharCode(i)}}t=Base64._utf8_decode(t);return t},_utf8_encode:function(e){e=e.replace(/\r\n/g,"\n");var t="";for(var n=0;n<e.length;n++){var r=e.charCodeAt(n);if(r<128){t+=String.fromCharCode(r)}else if(r>127&&r<2048){t+=String.fromCharCode(r>>6|192);t+=String.fromCharCode(r&63|128)}else{t+=String.fromCharCode(r>>12|224);t+=String.fromCharCode(r>>6&63|128);t+=String.fromCharCode(r&63|128)}}return t},_utf8_decode:function(e){var t="";var n=0;var r=c1=c2=0;while(n<e.length){r=e.charCodeAt(n);if(r<128){t+=String.fromCharCode(r);n++}else if(r>191&&r<224){c2=e.charCodeAt(n+1);t+=String.fromCharCode((r&31)<<6|c2&63);n+=2}else{c2=e.charCodeAt(n+1);c3=e.charCodeAt(n+2);t+=String.fromCharCode((r&15)<<12|(c2&63)<<6|c3&63);n+=3}}return t}}
var encodedString = Base64.encode(email).replace(/\+/g, '-').replace(/\//g, '_').replace(/\=+$/, '');
var sendRequest = gapi.client.gmail.users.messages.send({
'userId': 'me',
'resource': {
'raw': encodedString
}
});
我總是得到電子郵件與HTML標籤。
出於好奇，我直接通過Gmail發送了一封電子郵件，內容爲：<b>text<b>，並且收到了未格式化的郵件。但是，當我在Gmail中對其進行格式化時，它會收到文本。
所以我想知道是否有可能通過Gmail API發送富文本電子郵件？
編輯 全碼：
function sendEmail() {
$('#submit_compose').addClass('disabled');
var to = $("#compose-to").val();
var cc = $("#compose-cc").val();
var subject = $("#compose-subject").val();
var message = $("#compose-message").val();
if (to == "" || to == "null" || to == null) {
ShowNotification("danger", "Please specify at least one recipient!");
$('#submit_compose').removeClass('disabled');
} else if (!validateEmail(to)) {
ShowNotification("danger", "Please specify a valid email!");
$('#submit_compose').removeClass('disabled');
} else if (subject == "" || subject == "null" || subject == null) {
ShowNotification("danger", "Please specify a subject!");
$('#submit_compose').removeClass('disabled');
} else if (message == "" || message == "null" || message == null) {
$('#submit_compose').removeClass('disabled');
} else {
alert('ok');
sendMessage(
{
'To': $('#compose-to').val(),
'Subject': $('#compose-subject').val()
},
$('#compose-message').val(),
composeTidy
);
}
return false;
}
function sendMessage(headers_obj, message, callback) {
var email = '';
//message = '<b>hello</b>';
for(var header in headers_obj)
email += header += ": "+headers_obj[header]+"\r\n";
email += "\r\n" + message;
alert(email);
var sendRequest = gapi.client.gmail.users.messages.send({
'userId': 'me',
'resource': {
'raw': window.btoa(email).replace(/\+/g, '-').replace(/\//g, '_')
}
});
return sendRequest.execute(callback);
}
function composeTidy() {
$('#compose-modal').modal('hide');
$('#compose-to').val('');
$('#compose-subject').val('');
$('#compose-message').val('');
ShowNotification("success", "Message Sent!");
$('#submit_compose').removeClass('disabled');
}
這是可能的。你介意在問題中包括你的'email'嗎？ – Tholle
我使用CKEditor來創建富文本電子郵件。我可以在textarea上寫'test'，我可以寫'test'，然後通過'B'按鈕使它變成粗體，沒有區別。如果我忽略CKEditor並將消息設置爲message ='hello'（請參閱上面的代碼），否則我得到hello作爲未格式化 – erdomester
您是否包含內容類型頭？ 'Content-Type：text/html' – Tholle