解析：一次檢索不同表格中的所有數據

Question

我試圖從不同表格中獲取所有數據，因此我嘗試使用此方法。但是，我明白for循環是同步的，因此當解析正在獲取數據時，循環不會停止。有沒有人知道如何解決它？有沒有可能有助於這種情況的解析方法或某些意圖服務？

private void getAllInformation(){ 
    String controlName; 
    for(int i=0; i<3;i++){ 
     if(i==0){ 
      controlName = AppConfiguration.strEvent; 
     } 
     else if(i==1){ 
      controlName = AppConfiguration.strStore; 
     } 
     else if (i==2){ 
      controlName = AppConfiguration.strPromotion; 
     } 
     else{ 
      return; 
     } 

     ParseQuery<ParseObject> query = ParseQuery.getQuery(controlName); 
     query.findInBackground(new FindCallback<ParseObject>() { 
      public void done(List<ParseObject> objectList, ParseException e) { 
       if(e!=null){ 
        Toast.makeText(getApplicationContext(),"Error Loading.Please Try Again",Toast.LENGTH_LONG).show(); 
        return; 
       } 
       if (objectList!= null) { 
        Toast.makeText(getApplicationContext(),"Success",Toast.LENGTH_LONG).show(); 
        ParseObject.pinAllInBackground(objectList); 
       } 
       else{ 
        Toast.makeText(getApplicationContext(),"Some Data is null!",Toast.LENGTH_LONG).show(); 
       } 


      } 

     }); 

    } 


//  getAllOfflineInformation(); 
} 

Answer 1

您可以使用鎖：

Object lock = new Object(); 

ParseQuery<ParseObject> query = ParseQuery.getQuery(controlName); 
     query.findInBackground(new FindCallback<ParseObject>() { 
      public void done(List<ParseObject> objectList, ParseException e) { 
  synchronized (lock) { 
            lock.notifyAll(); 
        } 
       if(e!=null){ 
        Toast.makeText(getApplicationContext(),"Error Loading.Please Try Again",Toast.LENGTH_LONG).show(); 
        return; 
       } 
       if (objectList!= null) { 
        Toast.makeText(getApplicationContext(),"Success",Toast.LENGTH_LONG).show(); 
        ParseObject.pinAllInBackground(objectList); 
       } 
       else{ 
        Toast.makeText(getApplicationContext(),"Some Data is null!",Toast.LENGTH_LONG).show(); 
       } 


      } 

     }); 

synchronized (lock) { 
    lock.wait(); 
}