我想在sqlite中創建表,但它顯示錯誤,表不能創建。我有一個相同的代碼,但數據庫和表名稱是不同的。這些字段是相同的。還有一個疑問。我無法在包含相同字段的同一個數據庫中創建不同的表。sqlite。表沒有創建
DbAdapter.java
代碼如下。
public class DbAdapter {
private static final String DATABASE_NAME="bible1";
private static final String DATABASE_TABLE="test1";
private static final int DATABASE_VERSION=1;
public static final String KEY_ID="_id";
public static final String UNITS="units";
public static final String CHAPTERS="chapters";
private static final String CREATE_DATABASE="create table test1 (_id integer primary key autoincrement, units text not null, chapters text not null);";
private SQLiteHelper sqLiteHelper;
private static SQLiteDatabase sqLiteDatabase;
private Context context;
//constructor
public DbAdapter(Context c){
context = c;
}
private static class SQLiteHelper extends SQLiteOpenHelper{
public SQLiteHelper(Context context){
super(context,DATABASE_NAME,null,DATABASE_VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
// TODO Auto-generated method stub
db.execSQL(CREATE_DATABASE);
MakeUnits();
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
// TODO Auto-generated method stub
}
}
public DbAdapter open() throws SQLException{
try{
sqLiteHelper = new SQLiteHelper(context);
sqLiteDatabase = sqLiteHelper.getWritableDatabase();
}catch(NullPointerException ne){
Log.e("error in creating the table", "bye");
}
return this;
}
public void close(){
sqLiteHelper.close();
}
public static long MakeUnits()
{
ContentValues insert1 = new ContentValues();
insert1.put(UNITS, "Unit1");
insert1.put(CHAPTERS, "CHAPTER1");
return sqLiteDatabase.insert(DATABASE_TABLE,null,insert1);
}
public Cursor fetchAllNotes(){
return sqLiteDatabase.query(DATABASE_TABLE, new String[]{KEY_ID,UNITS,CHAPTERS}, null, null, null, null, null);
}
}
MainActivity.java
public class MainActivity extends ListActivity {
private DbAdapter Database;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ListView listContent = (ListView) findViewById(android.R.id.list);
Database= new DbAdapter(this);
Database.open();
Cursor c = Database.fetchAllNotes();
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.activity_main, menu);
return true;
}
}
這是給錯誤時,open()方法被調用。無法弄清楚。 在logcat的標記中的錯誤是「在創建表錯誤」
請您提供更多信息,如錯誤消息或呼叫跟蹤? – flypen
在DbAdapter的open()方法中,它給出了錯誤。如果你寄給我你的郵件,那麼我可以郵寄代碼。 – test1990bdvt
我不能在同一個數據庫中有兩個具有相同字段名稱的表。 – test1990bdvt