合併相同鍵的數組值

Question

我正在嘗試構建一個查詢字符串以用作Google字體選擇。字體名稱和權重將作爲數組傳遞。

$fonts = array(); 

$fonts[] = array('family' => 'Lato', 'weight' => '400',); 
$fonts[] = array('family' => 'Lato', 'weight' => '700i',); 
$fonts[] = array('family' => 'Lato', 'weight' => '900',); 
$fonts[] = array('family' => 'Open Sans', 'weight' => '400',); 
$fonts[] = array('family' => 'Open Sans', 'weight' => '700',); 
$fonts[] = array('family' => 'Open Sans', 'weight' => '800',); 
$fonts[] = array('family' => 'Ubuntu', 'weight' => '400',); 
$fonts[] = array('family' => 'Ubuntu', 'weight' => '500',); 
$fonts[] = array('family' => 'Ubuntu', 'weight' => '7i00',); 

如果字體系列相同，如何合併權重？這樣它變成這樣嗎？

Array 
(
    [Lato] => 400,700i,900 
    [Open+Sans] => 400,700,800 
    [Ubuntu] => 400,500,700i 
) 

，因爲我處理的其他答案的單一陣列，沒有我不能使用array_merge_recursive這裏幫助我。

如果您打算將此問題標記爲重複，請注意在詢問之前我已嘗試了幾個答案。他們都沒有工作。

Answer 1

採用單foreach()就可以實現它象下面這樣： -

$new_array = array(); 

foreach ($fonts as $font){ 
    $new_value = !empty($new_array[$font['family']]) ? $new_array[$font['family']].','.$font['weight'] : $font['weight']; 
    $new_array[$font['family']] = $new_value; 
} 

echo "<pre/>";print_r($new_array); 

輸出： - https://eval.in/681838

Answer 2

使用兩foreach語句來達到這個

$newArr = array(); 
//make an array values for each family 
foreach ($fonts as $val) { 
    $newArr[$val['family']][] = $val['weight']; 
} 
//using implode join the array values 
foreach ($newArr as &$val) { 
    $val = implode(', ', $val); 
} 

var_dump($newArr); // would be the required array 

Answer 3

你可以做手工用一個foreach聲明。

function mergeFonts($fonts) 
{ 
    $result = array(); 
    foreach ($fonts as $font) { 
     if (array_key_exists($font['family'], $result)) { 
      array_push($result[$font['family']], $font['weight']); 
     } else { 
      $result[$font['family']] = array($font['weight']); 
     } 
    } 
    return $result; 
} 

和：

$fonts = array(); 
    $fonts[] = array('family' => 'Lato', 'weight' => '400',); 
    $fonts[] = array('family' => 'Lato', 'weight' => '700i',); 
    $fonts[] = array('family' => 'Lato', 'weight' => '900',); 
    $fonts[] = array('family' => 'Open Sans', 'weight' => '400',); 
    $fonts[] = array('family' => 'Open Sans', 'weight' => '700',); 
    $fonts[] = array('family' => 'Open Sans', 'weight' => '800',); 
    $fonts[] = array('family' => 'Ubuntu', 'weight' => '400',); 
    $fonts[] = array('family' => 'Ubuntu', 'weight' => '500',); 
    $fonts[] = array('family' => 'Ubuntu', 'weight' => '7i00',); 
    echo '<pre>'; 
    print_r(mergeFonts($fonts)); 
    /* The output: 
    Array 
    (
     [Lato] => Array 
      (
       [0] => 400 
       [1] => 700i 
       [2] => 900 
      ) 

     [Open Sans] => Array 
      (
       [0] => 400 
       [1] => 700 
       [2] => 800 
      ) 

     [Ubuntu] => Array 
      (
       [0] => 400 
       [1] => 500 
       [2] => 7i00 
      ) 

    ) 
    */ 

Answer 4

當然，有其他人已經提到的香草PHP解決方案，但我會去Laravel的Collection類。

這是不限於Laravel雖然應用程序，您只需安裝一個作曲家包，除了解決這方面的問題，它帶來了很多善良的你的應用程序，並在您的處置有用的工具屈指可數。讓我們看看：

collect($fonts) 
    ->groupBy('family') 
    ->map(function($item, $key) { 
     return $item->pluck('weight'); 
    }) 
    ->toArray(); 

就這麼簡單。這裏的輸出：

[ 
    "Lato" => [ 
      "400", 
      "700i", 
      "900", 
    ], 
    "Open Sans" => [ 
      "400", 
      "700", 
      "800", 
    ], 
    "Ubuntu" => [ 
      "400", 
      "500", 
      "7i00", 
    ], 
] 

你可能想繼續並implode值。

如果不使用Laravel，這裏是standalone package for Laravel's Collection類。安裝，只是composer require tightenco/collect的問題。你只是安裝一個包，而不是整個框架。