將n個字符組合在一個列表中

Question

我試圖結合n個表（包含字典的列表），如果常用鍵具有相同的值。因此我使用* arg和另外兩個表.my代碼工作正常與兩張桌子，但由於某些未知的原因*參數沒有返回。 我的代碼：

def join(tbl1, tbl2, *args): 
    _dic = {} 
    _list = [] 
    dictsOutOfArgs = [] 
    for d in args: 
     dictsOutOfArgs.append(d) 
    for t1, t2 , arg in zip(tbl1, tbl2, dictsOutOfArgs): 
     for i , j , z in zip(t1, t2, arg): 
      if i == j == z and t1.get(i) == t2.get(j) == arg.get(z): 
       _dic = t1.copy() 
       _dic.update(t2) 
       _dic.update(arg) 
       _list.append(_dic) 

    return _list 

if __name__ == '__main__': 
    import pprint 
    print(test_answer()) 
    print(test_answer1()) 
    series = [ 
    {'s_id': 'bb', 'title': 'Breaking Bad'}, 
    {'s_id': 'bcs', 'title': 'Better Call Saul'}] 
    characters = [ 
    {'c_id': 'ww', 'family_name': 'White', 'given_name': 'Walter'}, 
    {'c_id': 'sw', 'family_name': 'White', 'given_name': 'Skyler'}, 
    {'c_id': 'sg', 'family_name': 'Goodman', 'given_name': 'Saul'}] 
    series_characters = [ 
    {'c_id': 'ww', 's_id': 'bb'}, 
    {'c_id': 'sw', 's_id': 'bb'}, 
    {'c_id': 'sg', 's_id': 'bb'}, 
    {'c_id': 'sg', 's_id': 'bcs'}] 
    x = join(series_characters, series, characters) 

    pprint.pprint(x) 

預期輸出：

[{'c_id': 'ww', 
    'family_name': 'White', 
    'given_name': 'Walter', 
    's_id': 'bb', 
    'title': 'Breaking Bad'}, 
    {'c_id': 'sw', 
    'family_name': 'White', 
    'given_name': 'Skyler', 
    's_id': 'bb', 
    'title': 'Breaking Bad'}, 
    {'c_id': 'sg', 
    'family_name': 'Goodman', 
    'given_name': 'Saul', 
    's_id': 'bb', 
    'title': 'Breaking Bad'}, 
    {'c_id': 'sg', 
    'family_name': 'Goodman', 
    'given_name': 'Saul', 
    's_id': 'bcs', 
    'title': 'Better Call Saul'}] 

回報是：[] ，我認爲原因是argss沒有任何價值，所以如果條件返回false。

有什麼想法？

Answer 1

也許這樣的事情（注意它有點挑剔表的順序排列）：

def join(tbl1, *args): 
    ret_list = [] 
    for obj in tbl1: 
     consolidated = obj.copy() 
     for join_tbl in args: 
      keys = consolidated.viewkeys() & join_tbl[0].viewkeys() 
      match_obj = next(o for o in join_tbl if all(consolidated.get(k) == o.get(k) for k in keys)) 
      if match_obj: 
       consolidated.update(match_obj) 
     ret_list.append(consolidated) 
    return ret_list 

join(series_characters, series, characters)回報

{'c_id': 'ww', 'given_name': 'Walter', 'title': 'Breaking Bad', 's_id': 'bb', 'family_name': 'White'} 
{'c_id': 'sw', 'given_name': 'Skyler', 'title': 'Breaking Bad', 's_id': 'bb', 'family_name': 'White'} 
{'c_id': 'sg', 'given_name': 'Saul', 'title': 'Breaking Bad', 's_id': 'bb', 'family_name': 'Goodman'} 
{'c_id': 'sg', 'given_name': 'Saul', 'title': 'Better Call Saul', 's_id': 'bcs', 'family_name': 'Goodman'}