我有以下表現:不能夠命令由包括在Rails3中
user.clocks.includes(:users, :runs => :user_runs).find_by_id(params[:id])
這似乎很好地工作。但是,當我添加一個命令,就像這樣:
user.clocks.includes(:users, :runs => :user_runs).orders("users.names").find_by_id(params[:id])
它打破,出現以下錯誤:
ActiveRecord::ConfigurationError: Association named 'user_runs' was not found; perhaps you misspelled it?
app/controllers/clocks_controller.rb:19:in `show'
test/functional/clocks_controller_test.rb:21:in `__bind_1286475263_942556'
任何想法,爲什麼?
這個模型看起來是這樣的:
class Clock < ActiveRecord::Base
has_and_belongs_to_many :users
has_many :runs
end
class Run < ActiveRecord::Base
belongs_to :clock
has_many :user_runs
has_many :users, :through => :user_runs
end
class UserRun < ActiveRecord::Base
belongs_to :run
belongs_to :user
end
與我調查繼續我已經試過這樣:
ubiquitous_user.clocks.includes(:runs => :user_runs).find_by_id(params[:id])
而且我發現它的發電查詢沒有得到user_runs在所有。有些事情很奇怪。
我創建了一組測試,試圖找出發生了什麼事情:
context "A graph of users, clocks, runs, etc" do
setup do
@users = []
10.times do
@users << Factory.create(:user)
end
@clocks = []
10.times do
@clocks << Factory.create(:clock, :users => @users)
end
@clocks.each do |clock|
10.times do
run = Factory.create :run, :clock => clock
@users.each do |user|
Factory.create :user_run, :run => run, :user => user
end
end
end
@user = @users.first
@clock = @clocks.first
end
should "find a clock" do
assert_not_nil @user.clocks.find(@clock.id)
end
should "find a clock with users" do
assert_not_nil @user.clocks.includes(:users).find(@clock.id)
end
should "find a clock with users and runs" do
assert_not_nil @user.clocks.includes(:users, :runs).find(@clock.id)
end
should "find a clock with users, runs and user_runs" do
assert_not_nil @user.clocks.includes(:users, :runs => :user_runs).find(@clock.id)
end
should "find a clock with users order by users.name" do
assert_not_nil @user.clocks.includes(:users).order("users.name").find(@clock.id)
end
should "find a clock with users and runs order by users.name" do
assert_not_nil @user.clocks.includes(:users, :runs).order("users.name").find(@clock.id)
end
should "find a clock with users, runs and user_runs order by users.name" do
assert_not_nil @user.clocks.includes(:users, :runs => :user_runs).order("users.name").find(@clock.id)
end
end
每個測試,但最後一道關口。這不是一個錯誤?
不能在Rails 3中,據我所知。這是舊的Rails 2風格;但它應該仍然有效,也許它工作。我會試一試。 – Pablo 2010-10-08 04:40:27
有了這種語法,它似乎工作。感謝您的想法! :) – Pablo 2010-10-08 05:09:59
實際上,它在一種情況下工作,但沒有在另一種情況下。 – Pablo 2010-10-08 11:41:52