如何在索引落後時在PHP數組中進行換行？

Question

我希望能夠通過使用數字鍵檢索數組的值。問題是，如果鍵超出了數組長度，我需要它再次遍歷數組。

$my_array = array('zero','one','two','three','four','five','six','seven'); 
function loopArrayValues($array,$key){ 
    //this is what is needed to return 
    return 
} 
echo "Key 2 is ".loopArrayValues($my_array,2)."<br />"; 
echo "Key 11 is ".loopArrayValues($my_array,11)."<br />"; 
echo "Key 150 is ".loopArrayValues($my_array,11)."<br />"; 

預期輸出：

Key 2 is two 
Key 11 is three 
Key 150 is three 

我研究的參考資料：

• continuously loop through PHP array (or object keys)
• http://php.net/manual/en/class.infiniteiterator.php

我生成的功能：

function loopArrayValues($array,$key){ 
    $infinate = new InfiniteIterator(new ArrayIterator($array)); 
    foreach(new LimitIterator($infinate,1,$key) as $value){ 
    $return=$value; 
    } 
    return $return; 
} 

該函數的工作原理，但我有一個問題：這是獲得預期結果的好方法嗎？

Answer 1

你太複雜了，除非你真的想處理數組中的元素，因爲它很貴，所以你不想迭代它們。我想你只需要的元素數量的模量陣列中，像這樣： -

$my_array = array('zero', 'one','two','three','four','five','six','seven'); 

function loopArrayValues(array $array, $position) 
{ 
    return $array[$position % count($array)]; 
} 

for($i = 0; $i <= 100; $i++){ 
    echo "Position $i is " . loopArrayValues($my_array, $i) . "<br/>"; 
} 

輸出繼電器： -

Position 0 is zero 
Position 1 is one 
Position 2 is two 
Position 3 is three 
Position 4 is four 
Position 5 is five 
Position 6 is six 
Position 7 is seven 
Position 8 is zero 
Position 9 is one 
Position 10 is two 
Position 11 is three 
Position 12 is four 
Position 13 is five 

等等