Django註冊模塊success_url沒有返回

Question

我正在自定義django註冊模塊。到目前爲止，我傳遞的URL像

from django.conf.urls import patterns, include, url 

# Uncomment the next two lines to enable the admin: 
# from django.contrib import admin 
# admin.autodiscover() 

from django.contrib import admin 
admin.autodiscover() 
from django.conf.urls.defaults import * 
from django.views.generic.simple import direct_to_template 
import registration.backends.default.urls as regUrls 

from profile import UserRegistrationForm 
from registration.views import register 
import regbackend, views 
from accounts import profile 
urlpatterns = patterns('',  
    # (r'^conf/admin/(.*)', admin.site.root), 
    url(r'^register/$', register, {'backend': 'registration.backends.default.DefaultBackend','success_url':profile,'form_class': UserRegistrationForm}, name='registration_register'), 
    (r'^accounts/', include(regUrls)), 
    url('^profile/$', direct_to_template, {'template': 'profile.html'}, name="profile"), 


) 

當URL請求我的錯誤No module named django.views，它是不會去success_url。

我想我在做錯了urls.py但我看不到什麼。請幫助我。

在此先感謝。

Answer 1

嘗試改變這一行：

url(r'^register/$', register, {'backend': 'registration.backends.default.DefaultBackend','success_url':profile,'form_class': UserRegistrationForm}, name='registration_register'), 

要這樣：

url(r'^register/$', 
    RegistrationView.as_view(
     form_class=UserRegistrationForm, 
     success_url='profile/',), 
    name='registration_register', 
    ), 

我沒有在這裏使用了一個名爲URL，但它可以更容易把它與一個硬編碼的工作都當你確定一切正常時，將它改爲命名。