2013-01-03 33 views
1

我使用下面的類來獲取一些JSON數據。奇怪的是,我無法僅從我需要測試應用程序的url(服務器端不是由我維護)解析JSON:如果您單擊this link,您將能夠在瀏覽器中看到JSON數據。但是當我嘗試以編程方式解析它時,它會引發JSONException。當試圖解析JSON數據時android JSONException

01-03 11:08:23.615: E/JSON Parser(19668): Error parsing data org.json.JSONException: Value <html><head><title>JBoss of type java.lang.String cannot be converted to JSONObject 

我試着用http://ip.jsontest.com/http://api.androidhive.info/contacts進行測試,它很好地工作!只有在嘗試從我的第一個鏈接解析JSON時才引發異常。我認爲這可能是一個服務器問題,但我能夠用瀏覽器查看JSON數據..只是無法解釋這一點。

public class JSONParser { 

static InputStream is = null; 
static JSONObject jObj = null; 
static String json = ""; 

/* default constuctor*/ 
public JSONParser() { 

} 

public JSONObject getJSONFromUrl(String url) { 

    /* get JSON via http request */ 
    try { 

     DefaultHttpClient httpClient = new DefaultHttpClient(); 
     HttpPost httpPost = new HttpPost(url); 

     HttpResponse httpResponse = httpClient.execute(httpPost); 
     HttpEntity httpEntity = httpResponse.getEntity(); 
     is = httpEntity.getContent();   

    } catch (UnsupportedEncodingException e) { 
     e.printStackTrace(); 
    } catch (ClientProtocolException e) { 
     e.printStackTrace(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 

    try { 
     BufferedReader reader = new BufferedReader(new InputStreamReader(
       is, "iso-8859-1"), 8); 
     StringBuilder sb = new StringBuilder(); 
     String line = null; 
     while ((line = reader.readLine()) != null) { 
      sb.append(line + "\n"); 
     } 
     is.close(); 
     json = sb.toString(); 
    } catch (Exception e) { 
     Log.e("Buffer Error", "Error converting result " + e.toString()); 
    } 

    /* try to parse the string to JSON Object*/ 
    try { 
     jObj = new JSONObject(json); 
    } catch (JSONException e) { 
     Log.e("JSON Parser", "Error parsing data " + e.toString()); 
    } 

/* return JSON String */ 
    return jObj; 

     } 
    } 
+2

看起來您實際上正在收到JBoss錯誤消息。我想添加一個'System.err.println(json);'看看你實際上試圖解析什麼...... – beny23

+0

你的問題是在jObj = new JSONObject(json); ,檢查你的字符串'json'是否包含任何奇怪的符號或html。 –

+0

是...值 ..........但是爲什麼? – <span class="text-secondary"> <small> <a rel="noopener" target="_blank" href="https://stackoverflow.com/users/1199662/">Droidman</a></span> <span></span> </small> </span> </p> </div> </div> </div> </div> </div> </article> </div> <div class="answer-title"> <span class="text-logo margin-top-sm">A</span> <h2 class="title h4">回答</h2> </div> <div class="item-description text-md markdown-body margin-bottom-40 voidso"> <article class="board-top-1 padding-top-10"> <div class="post-col vote-info"> <span class="count">1<i class="fa fa-thumbs-up"></i></span> <i class="fa fa-check fa-2x"></i> </div> <div class="post-offset"> <div class="answer fmt"> <p>使用的BufferedReader辦法去給你拿的是網頁的HTML源代碼,這就是爲什麼你看到的HTML標籤,如< HTML> <頭> <標題>在您的字符串。相反,使用EntityUtils來獲取JSON字符串:</p> <pre><code class="prettyprint-override">DefaultHttpClient httpClient = new DefaultHttpClient(); HttpGet httpGet = new HttpGet(url); try { HttpResponse httpResponse = httpClient.execute(httpGet); HttpEntity httpEntity = httpResponse.getEntity(); int status = httpResponse.getStatusLine().getStatusCode(); if (status == HttpStatus.SC_OK) { String jsonString = EntityUtils.toString(httpEntity); try { JSONObject jsonObject = new JSONObject(jsonString); } catch (JSONException e) { e.printStackTrace(); } } } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } </code></pre> </div> <div class="post-info"> <div class="post-meta row"> <p class="text-secondary col-lg-6"> <span class="source"> <a rel="noopener" target="_blank" href="https://stackoverflow.com/q/14391474">來源</a> </span> </p> <p class="text-secondary col-lg-6"> <span class="float-right date"> <span>2013-01-18 02:19:27</span> </p> <p class="col-12"></p> <p class="col-12"></p></div> </div> <!-- comments --> <div class="comments"> <div itemprop="comment" class="post-comment"> <div class="row"> <div class="col-lg-1"><span class="text-secondary">+0</span></div> <div class="col-lg-11"> <p class="commenttext">當我嘗試.....在jsonString :: >>>我沒有得到整個數據.. 。你知道如何管理它嗎? – <span class="text-secondary"> <small> <span></span> </small> </span> </p> </div> </div> </div> <div itemprop="comment" class="post-comment"> <div class="row"> <div class="col-lg-1"><span class="text-secondary">+0</span></div> <div class="col-lg-11"> <p class="commenttext">, 「medium」:{ 「url」:「https://i.ytimg.com/vi/zUaMzFrRLWg/mqdefault.jpg」, 「width ...」最後,我得到了「...」如何獲取整個數據「 – <span class="text-secondary"> <small> <span></span> </small> </span> </p> </div> </div> </div> </div> </div> </article> <div> <script async src="https://pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script> <ins class="adsbygoogle" style="display:block" data-ad-client="ca-pub-6208739752673518" data-ad-slot="1038284119" data-ad-format="auto" data-full-width-responsive="true"></ins> <script> (adsbygoogle = window.adsbygoogle || []).push({}); </script> </div> </div> <div class="clearfix"> </div> <div class="relative-box"> <div 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