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爲什麼我得到的錯誤,如果我運行這段代碼?:「Range.Find」測試白白寫着「必選對象」
Dim mitarbeiterStatus
Dim mitarbeiterCell As Variant
Set mitarbeiterCell = Nothing
Dim rowsinWorkflow As Integer
rowsinWorkflow = Worksheets("worksheet1").Range("A1").End(xlDown).Row
With Worksheets("worksheet1").Range("B2:B" & rowsinWorkflow)
Dim firstAddress
mitarbeiterCell = .Find(displayName, LookIn:=xlValues)
If Not mitarbeiterCell Is Nothing Then 'ERROR HERE
firstAddress = mitarbeiterCell.Address
Do
'.....
Set mitarbeiterCell = .FindNext(displayName)
Loop While Not c Is Nothing And mitarbeiterCell.Address <> firstAddress
我試圖做喜歡這裏的對象是必需的方式:https://msdn.microsoft.com/de-de/library/office/ff839746.aspx
With Worksheets(1).Range("a1:a500")
Set c = .Find(2, lookin:=xlValues)
If Not c Is Nothing Then
firstAddress = c.Address
Do
c.Value = 5
Set c = .FindNext(c)
Loop While Not c Is Nothing And c.Address <> firstAddress
End If
End With
它可能是值得的聲明'mitarbeiterCell'作爲'Range'一樣,所以:'昏暗mitarbeiterCell作爲Range' –
你可以,但沒有什麼錯誤使用一個變種持有對象。 –