插入MySQL行但未保存？

Question

我插入一個行從PHP一個MySQL表和插入後立即運行一個查詢來獲取剛插入像這樣的行的鍵值：

$stmt = $this->db->prepare("INSERT INTO user(vFirstName, vLastName, vEmail, vPassword, iSkilllevelid, vTournaments, vDays, dAddedDate, eStatus) VALUES (?,?,?,?,4,'Pick-Up','Saturday',NOW(),'Active')"); 
$stmt->bind_param("ssss", $firstName, $lastName, $email, $pwd); 
$stmt->execute(); 
$stmt->close(); 

$stmt = $this->db->prepare('SELECT iUserId FROM user WHERE vEmail=?'); 
$stmt->bind_param("s", $email); 
$stmt->execute(); 
$stmt->bind_result($iUserId); 
while ($stmt->fetch()) { 
    break; 
} 

該代碼執行後，$iUserId有正確的自動遞增鍵值（例如1143），但是當我真正查看數據庫表時，具有該鍵（1143）的行不存在。這怎麼可能？

Answer 1

而是在插入後的表中選擇的，你應該使用mysqli::$insert_id：

$stmt = $this->db->prepare(' 
    INSERT INTO user 
    (vFirstName, vLastName, vEmail, vPassword, iSkilllevelid, 
     vTournaments, vDays, dAddedDate, eStatus) 
    VALUES 
    (?,?,?,?,4,"Pick-Up","Saturday",NOW(),"Active") 
'); 
$stmt->bind_param('ssss', $firstName, $lastName, $email, $pwd); 
$stmt->execute(); 
$iUserId = $this->db->insert_id; 
$stmt->close(); 

至於爲什麼要插入的數據不能從其他的連接出現，這很可能是您的交易還未被提交：

$this->db->commit();