我對JSON/Spring MVC非常新,並試圖獲得一個簡單的AJAX調用Spring MVC控制器的例子 - 但我一直返回一個錯誤400 - 錯誤請求。與JQuery/Ajax和Spring的JSON請求
經過淘汰互聯網後,我發現這通常是由於沒有設置適當的內容類型導致 - 但[我相信]我已經這樣做了。
這裏是我的AJAX調用:
//validate the object
var urlString = "/ajax/add/";
$.ajax({
type:"POST",
url: urlString,
contentType: "application/json; charset=utf-8",
dataType: "json",
data: {value1: 'apples', value2 : 'oranges'},
success: function(result){
alert("success");
},
error: function(jqXHR, textStatus, errorThrown){
alert("error:" + textStatus + " exception:" + errorThrown);
}
}) ;
而且我的控制器:
@Controller
itpublic class AddController {
private static Logger m_log = null;
@RequestMapping(value = "/ajax/add")
public String handle(@RequestBody String json){
DummyClass dummyRequest;
try {
ObjectMapper mapper = new ObjectMapper();
dummyRequest = mapper.readValue(json, DummyClass.class);
m_log.info("Value1: " + dummyRequest.getValue1());
m_log.info("Value2: " + dummyRequest.getValue2());
} catch (Exception e) {
}
finally{
}
return "called";
}
誰能幫助我嗎?
編輯
這裏是我的背景下,我用它來配置Spring:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:p="http://www.springframework.org/schema/p" xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="com.project.do" />
<!--<mvc:annotation-driven/> -->
<bean class="com.project.do.interceptors.handler.mapping.HandlerInterceptorAnnotationAwareHandlerMapping "/>
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter" />
<bean class="com.project.do.viewresolver.ProjectViewResolver" >
<property name="tilesResolver" ref="tilesResolver" />
<property name="jspResolver" ref="jspResolver" />
</bean>
<bean id="tilesResolver" class ="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.tiles2.TilesView" />
<property name="order" value="2" />
</bean>
<bean id="jspResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
<property name="order" value="3" />
</bean>
<bean id ="tilesConfigurer" class="org.springframework.web.servlet.view.tiles2.TilesConfigurer">
<property name="definitions" value="/WEB-INF/tiles/tiles.xml" />
<property name="preparerFactoryClass" value="org.springframework.web.servlet.view.tiles2.SpringBeanPreparerFactory"/>
</bean>
<mvc:resources mapping="/css/**" location="/css/" />
<mvc:resources mapping="/js/**" location="/js/" />
<mvc:resources mapping="/images/**" location="/images/" />
<mvc:resources mapping="/javascript/**" location="/javascript/" />
<mvc:resources mapping="/scripts/**" location="/scripts/" />
<mvc:resources mapping="/styles/**" location="/styles/" />
<mvc:resources mapping="/help/**" location="/help/" />
<!-- <mvc:view-controller path="/" view-name="welcome"/> -->
我要指出,我有阿賈克斯工作控制器在包com.project .do.working,但帶有Ajax和JSON的非工作控制器位於同一個包中com.project.do.not.working
你是如何配置Spring?你可以編輯問題並添加你的配置細節(可能是一個XML文件,除非你使用新的@Configuration風格)。 – andyb 2012-04-20 21:38:49
我附加了用於配置Spring的上下文。謝謝! – kjl 2012-04-20 21:50:32
您可以嘗試用@RequestParam字符串value1替換您的RequestBody,..(at)RequestParam字符串value2?你確實想在你的ReequestMapping中有方法= RequestMethod.POST(正如raddykrish所說的那樣)。 – Stealth 2012-04-21 04:30:24