可變參數構造函數繼承

Question

template<typename Type, size_t Dimensions> 
struct Base 
{ 
    template <typename ... Args> 
    Base (const Args& ... args) : /*initialize*/ {} 
/* 
some functionality 
*/ 
}; 

template<size_t Dimensions> 
using myBase = typename Base<_DOUBLE,Dimensions> ; 

template<size_t Dimensions> 
class Derived: public myBase<Dimensions> 
{ 
/* 
some additional functionality 
*/ 
} 

myBase<2> mB(1.0,2.0); //works 
Derived<2> D(1.0,2.0); //error C2661: 'Derived<2>::Derived': no overloaded function takes 2 arguments 

爲什麼構造函數的隱式繼承不起作用，如果有必要，在這種情況下如何創建正確的構造函數？

Answer 1

沒有必要的typename這裏：

using myBase = typename Base<_DOUBLE,Dimensions> ; 

構造函數是不能繼承的，除非與using關鍵字明確地規定（見Inheriting constructors）。

template<size_t Dimensions> 
class Derived: public myBase<Dimensions> 
{ 
public: 
    using myBase<Dimensions>::myBase; 
};