在php中提交表單後，如何在文本框中輸入數據？

我希望在表單提交後，將輸入的數據保存在我的表單中。我只在第一個文本框中測試函數「VALUE =」「」，但是當我填寫文本框並提交表單時，文本框中出現通知錯誤，其中顯示「
注意：Undefined變量：/web/stud/u0867587/MOBILEPHP/exam_interface.php在線
「中的sessionid。當我在互聯網上看到如何正確地做到這一點時，它們都按照我所做的方式來做。那麼爲什麼它不能正常工作，你能幫我解決這個問題。在php中提交表單後，如何在文本框中輸入數據？

下面是代碼：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 

<title>Exam Interface</title> 
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> 
</head> 
<body> 

<p><strong>NOTE: </strong>If a search box is left blank, then the form will search for all data under that specific field</p> 

<form action="exam_interface.php" method="post" name="sessionform">  <!-- This will post the form to its own page"--> 
<p>Session ID: <input type="text" name="sessionid" value="<?PHP print $sessionid ; ?>" /></p>  <!-- Enter Session Id here--> 
<p>Module Number: <input type="text" name="moduleid" /></p>  <!-- Enter Module Id here--> 
<p>Teacher Username: <input type="text" name="teacherid" /></p>  <!-- Enter Teacher here--> 
<p>Student Username: <input type="text" name="studentid" /></p>  <!-- Enter User Id here--> 
<p>Grade: <input type="text" name="grade" /></p>  <!-- Enter Grade here--> 
<p>Order Results By: <select name="order"> 
<option value="ordersessionid">Session ID</option> 
<option value="ordermoduleid">Module Number</option> 
<option value="orderteacherid">Teacher Username</option> 
<option value="orderstudentid">Student Username</option> 
<option value="ordergrade">Grade</option> 
</select> 
<p><input type="submit" value="Submit" name="submit" /></p> 
</form> 

<?php 

$username="xxx"; 
$password="xxx"; 
$database="mobile_app"; 

mysql_connect('localhost',$username,$password); 

@mysql_select_db($database) or die("Unable to select database"); 

if(isset($_POST['submit'])) { 

$sessionid = isset ($_POST['sessionid']) ? $_POST['sessionid'] : ""; 
$moduleid = isset ($_POST['moduleid']) ? $_POST['moduleid'] : ""; 
$teacherid = isset ($_POST['teacherid']) ? $_POST['teacherid'] : ""; 
$studentid = isset ($_POST['studentid']) ? $_POST['studentid'] : ""; 
$grade = isset ($_POST['grade']) ? $_POST['grade'] : ""; 
$orderfield = isset ($_POST['order']) ? $_POST['order'] : ""; 

$sessionid = mysql_real_escape_string($sessionid); 
$moduleid = mysql_real_escape_string($moduleid); 
$teacherid = mysql_real_escape_string($teacherid); 
$studentid = mysql_real_escape_string($studentid); 
$grade = mysql_real_escape_string($grade); 

?> 

</body> 
</html>

請幫忙，謝謝。

來源

2011-10-15 BruceyBandit

您正在使用$sessionid之前 retroting它。把你的PHP指令放在html部分之前。

來源

2011-10-15 15:56:44 Toto

將您的PHP代碼放在HTML文件之前，並將字段的值設置爲在發佈後捕獲它的變量。

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
    <head> 
     <title>Exam Interface</title> 
     <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> 
    </head> 
    <body> 

     <?php 
      $username="xxx"; 
      $password="xxx"; 
      $database="mobile_app"; 

      mysql_connect('localhost',$username,$password); 

      @mysql_select_db($database) or die("Unable to select database"); 

      if(isset($_POST['submit'])) { 
       $sessionid = isset ($_POST['sessionid']) ? $_POST['sessionid'] : ""; 
       $moduleid = isset ($_POST['moduleid']) ? $_POST['moduleid'] : ""; 
       $teacherid = isset ($_POST['teacherid']) ? $_POST['teacherid'] : ""; 
       $studentid = isset ($_POST['studentid']) ? $_POST['studentid'] : ""; 
       $grade = isset ($_POST['grade']) ? $_POST['grade'] : ""; 
       $orderfield = isset ($_POST['order']) ? $_POST['order'] : ""; 

       $sessionid = mysql_real_escape_string($sessionid); 
       $moduleid = mysql_real_escape_string($moduleid); 
       $teacherid = mysql_real_escape_string($teacherid); 
       $studentid = mysql_real_escape_string($studentid); 
       $grade = mysql_real_escape_string($grade); 
      } 
     ?> 
     <p><strong>NOTE: </strong>If a search box is left blank, then the form will search for all data under that specific field</p> 

     <form action="test.php" method="post" name="sessionform">  <!-- This will post the form to its own page"--> 
      <p>Session ID: <input type="text" name="sessionid" value="<?PHP print $sessionid ; ?>" /></p>  <!-- Enter Session Id here--> 
      <p>Module Number: <input type="text" name="moduleid" value="<?PHP print $moduleid ; ?>" /></p>  <!-- Enter Module Id here--> 
      <p>Teacher Username: <input type="text" name="teacherid" value="<?PHP print $teacherid ; ?>" /></p>  <!-- Enter Teacher here--> 
      <p>Student Username: <input type="text" name="studentid" value="<?PHP print $studentid ; ?>" /></p>  <!-- Enter User Id here--> 
      <p>Grade: <input type="text" name="grade" value="<?PHP print $grade ; ?>" /></p>  <!-- Enter Grade here--> 
      <p>Order Results By: <select name="order"> 
      <option value="ordersessionid" <?php if ($orderfield == "ordersessionid") echo 'selected="selected" '; ?>>Session ID</option> 
      <option value="ordermoduleid"> <?php if ($orderfield == "ordermoduleid") echo 'selected="selected" '; ?>Module Number</option> 
      <option value="orderteacherid" <?php if ($orderfield == "orderteacherid") echo 'selected="selected" '; ?>>Teacher Username</option> 
      <option value="orderstudentid" <?php if ($orderfield == "orderstudentid") echo 'selected="selected" '; ?>>Student Username</option> 
      <option value="ordergrade" <?php if ($orderfield == "ordergrade") echo 'selected="selected" '; ?>>Grade</option> 
      </select> 
      <p><input type="submit" value="Submit" name="submit" /></p> 
     </form> 

    </body> 
</html>

來源

2014-06-26 07:49:19 michikot

在php中提交表單後，如何在文本框中輸入數據？

回答

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