一直在奮鬥的年齡到創建一個水平的樹形佈局與矩形而不是圓形,並有文本包裝在那些矩形內。我沒有做似乎工作,我已經試過this code但任何人制造它已經離開了關鍵的一步,在該行 if (d.name.length > 26)
從停止運行整個腳本之前定義的變量d
。D3水平樹佈局與矩形和文字環繞
我也一直在努力,以包裹內rect
標籤文字使用d3plus.js從http://d3plus.org/但它實際上不工作一半時間,似乎需要像click
功能的觸發條件才能正常工作。同時考慮使用this example作爲文本換行的指南。
在我的研究我還沒有發現任何人做了水平,矩形的組合,在一個包裹圖表文本。 另外我有點d3 noob所以所有的幫助表示讚賞。
這裏是一個JSFiddle。
下面是當前的代碼我使用的是不工作:
var w = 960,
h = 2000,
i = 0,
duration = 500,
root;
var tree = d3.layout.tree()
.size([h, w - 160]);
var diagonal = d3.svg.diagonal()
.projection(function(d) { return [d.y, d.x]; });
var vis = d3.select("#container").append("svg:svg")
.attr("width", w)
.attr("height", h)
.append("svg:g")
.attr("transform", "translate(40,0)");
root = treeData[0];
root.x0 = h/2;
root.y0 = 0;
update(root);
function update(source) {
// Compute the new tree layout.
var nodes = tree.nodes(root).reverse();
// Update the nodes…
var node = vis.selectAll("g.node")
.data(nodes, function(d) { return d.id || (d.id = ++i); });
var nodeEnter = node.enter().append("svg:g")
.attr("class", "node")
.attr("transform", function(d) { return "translate(" + source.y0 + "," + source.x0 + ")"; });
// Enter any new nodes at the parent's previous position.
nodeEnter.append("svg:rect")
.attr("width", 150)
.attr("height", function(d) { return (d.name.length > 30) ? 38 : 19;})
.attr("y",-11)
.attr("rx",2)
.attr("ry",2)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; })
.on("click", click);
if (d.name.length > 26) {
nodeEnter.append("svg:text")
.attr("x", function(d) { return d._children ? -8 : 8; })
.attr("y", 3)
.text(function(d) { return d.name; });
} else {
nodeEnter.append("svg:text")
.attr("x", function(d) { return d._children ? -8 : 8; })
.attr("y", 3)
.append("svg:tspan")
.text(function(d) { return d.name.slice(0,26); })
.append("svg:tspan")
.attr("x", function(d) { return d._children ? -8 : 8; })
.attr("y",15)
.text(function(d) { return d.name.slice(26); });
}
}
// Transition nodes to their new position.
nodeEnter.transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; })
.style("opacity", 1)
.select("rect")
.style("fill", "lightsteelblue");
node.transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; })
.style("opacity", 1);
node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.style("opacity", 1e-6)
.remove();
// Update the links…
var link = vis.selectAll("path.link")
.data(tree.links(nodes), function(d) { return d.target.id; });
// Enter any new links at the parent's previous position.
link.enter().insert("svg:path", "g")
.attr("class", "link")
.attr("d", function(d) {
var o = {x: source.x0, y: source.y0};
return diagonal({source: o, target: o});
})
.transition()
.duration(duration)
.attr("d", diagonal);
// Transition links to their new position.
link.transition()
.duration(duration)
.attr("d", diagonal);
// Transition exiting nodes to the parent's new position.
link.exit().transition()
.duration(duration)
.attr("d", function(d) {
var o = {x: source.x, y: source.y};
return diagonal({source: o, target: o});
})
.remove();
// Stash the old positions for transition.
nodes.forEach(function(d) {
d.x0 = d.x;
d.y0 = d.y;
});
}
// Toggle children on click.
function click(d) {
if (d.children) {
d._children = d.children;
d.children = null;
} else {
d.children = d._children;
d._children = null;
}
update(d);
}
d3.select(self.frameElement).style("height", "2000px");
,以及我的JSON:
var treeData = [
{
"name": "Do trainees require direction as to what to do or how to do the task (either before they start or while they are completing it?",
"children": [
{
"name": "Can they satisfactorily complete the task assigned to them?",
"children": [
{
"name": "Rating level 4",
"parent": "A",
},
{
"name": "How many problems/queries are there that still need to be addressed/resolved to be able to satisfactorily complete the task?",
"children": [
{
"name": "Are problems/queries fundamental to the completion of the task at hand?",
"children": [
{
"name": "Rating level 4",
},
{
"name": "Can the problems be resolved by the trainee (after receiving guidance)?",
"children": [
{
"name": "Rating level 3",
},
{
"name": "Can the problems be resolved by the trainee (after receiving guidance)?",
"children": [
{
"name": "Rating level 2",
},
{
"name": "Rating level 1",
}
]
}
]
}
]
},
{
"name": "Are problems/queries fundamental to the completion of the task at hand?",
}
]
}
]
},
{
"name": "Can they satisfactorily complete the task assigned to them?",
"children": [
{
"name": "Rating 1",
},
{
"name": "Rating 2",
},
{
"name": "Rating 3",
},
{
"name": "Rating 4",
}
]
}
]
}];
你可能挽救了我的生命,我將盡快嘗試。 – 2015-02-23 20:12:31
這工作!有沒有辦法縮短初始路徑(從原點),以便它們不會伸展得那麼遠,有點像這樣http://blog.pixelingene.com/2011/07/building-a-tree-diagram-在-D3-JS / – 2015-02-23 21:58:15