MySQL查詢幫助

Question

我有以下5個表：

users(user_id) 
books(book_id, author_id) 
source_phrases(source_phrase_id, book_id, phrase) 
synonym_phrases(synonym_phrase_id, source_phrase_id, reader_id, synonym) 
synonym_ratings(synonym_ratings_id, synonym_phrase_id, rater_id, rating) 

我想獲得一個查詢，將選擇一個用戶已完成審查的所有書籍。

的用戶將完成審查一本書，如果他們所做每個源短語如下：

用戶已經提示了資源短語的同義詞（reader_id在synonym_phrases表是用戶ID）

OR

用戶已經額定源短語的同義詞（在synonym_ratings表rater_id是用戶ID）

我花了一整天試圖與無歡得到這個。任何幫助將非常感激。

Answer 1

SELECT b.* 
FROM books b 
WHERE book_id NOT IN 
     (
     SELECT sp.book_id 
     FROM source_phrases sp 
     WHERE source_phrase_id NOT IN 
       (
       SELECT syp.source_phrase_id 
       FROM synonym_phrases syp 
       WHERE reader_id = @user_id 
       ) 
       AND source_phrase_id NOT IN 
       (
       SELECT syp.source_phrase_id 
       FROM synonym_phrases syp 
       JOIN synonym_ratings sr 
       ON  sr.synonym_phrase_id = syp.synonym_phrase_id 
         AND sr.rater_id = @user_id 
       ) 
     ) 
     AND book_id IN 
     (
     SELECT sp.book_id 
     FROM source_phrases sp 
     )