我想創建一個腳本,獲取在瀏覽器URL p中varible和querys的colums playername對任何符合varible p但它仍然不工作的人知道我在做什麼錯我不停的擺弄這個幾個小時..
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Admin Panel</title>
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta name="description" content="">
<meta name="author" content="">
<link href="http://example.com/assets/css/bootstrap.css" rel="stylesheet">
<link href="http://example.com/assets/css/docs.css" rel="stylesheet">
<link href="http://example.com/assets/js/google-code-prettify/prettify.css" rel="stylesheet">
<center>
<?php
$con = mysql_connect("","","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("log", $con);
$plyr=$_GET["p"];
$result = mysql_query('SELECT * FROM logs_chat WHERE playername="$plyr"');
echo '
<table class="table">
<thead>
<tr>
<th>Time</th>
<th>Player</th>
<th>Message</th>
</tr>
</thead>
<tbody>
';
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['time'] . "</td>";
echo "<td>" . $row['playername'] . "</td>";
echo "<td>" . $row['text'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
</center>
<script type="text/javascript" src="http://platform.twitter.com/widgets.js"></script>
<script src="http://example.com/assets/js/jquery.js"></script>
<script src="http://example.com/assets/js/google-code-prettify/prettify.js"></script>
<script src="http://example.com/assets/js/bootstrap-transition.js"></script>
<script src="http://example.com/assets/js/bootstrap-alert.js"></script>
<script src="http://example.com/assets/js/bootstrap-modal.js"></script>
<script src="http://example.com/assets/js/bootstrap-dropdown.js"></script>
<script src="http://example.com/assets/js/bootstrap-scrollspy.js"></script>
<script src="http://example.com/assets/js/bootstrap-tab.js"></script>
<script src="http://example.com/assets/js/bootstrap-tooltip.js"></script>
<script src="http://example.com/assets/js/bootstrap-popover.js"></script>
<script src="http://example.com/assets/js/bootstrap-button.js"></script>
<script src="http://example.com/assets/js/bootstrap-collapse.js"></script>
<script src="http://example.com/assets/js/bootstrap-carousel.js"></script>
<script src="http://example.com/assets/js/bootstrap-typeahead.js"></script>
<script src="http://example.com/assets/js/bootstrap-affix.js"></script>
<script src="http://example.com/assets/js/application.js"></script>
</body>
</html>
**注意!** PHP的未來版本是*自嘲和刪除*了'mysql_'系列函數。看起來你仍然在學習PHP,這意味着現在對於[切換到PDO](http://php.net/book.pdo)或[mysqli](http://php.net)是一個很棒的時間。 /book.mysqli)。 – Charles
請學習使用參數化查詢。你現在擁有的是SQL注入。 http://bobby-tables.com/php.html有例子。 –
正常情況下,您沒有關閉** head **標籤並且不打開** body **標籤? – Dim13i