2015-10-06 43 views

回答

4

考慮這些測試:

require 'fruity' 

STR = '!' + ('a'..'z').to_a.join # => "!abcdefghijklmnopqrstuvwxyz" 

結果的單個字符開始的字符串:

compare do 
    _slice { STR[0] == '!' } 
    _start_with { STR.start_with?('!') } 
    _regex { !!STR[/^!/] } 
end 

# >> Running each test 32768 times. Test will take about 1 second. 
# >> _start_with is faster than _slice by 2x ± 1.0 
# >> _slice is similar to _regex 

結果開始的字符串的多個字符:

compare do 
    _slice { STR[0..4] == '!abcd' } 
    _start_with { STR.start_with?('!abcd') } 
    _regex { !!STR[/^!abcd/] } 
end 

# >> Running each test 32768 times. Test will take about 2 seconds. 
# >> _start_with is faster than _slice by 2x ± 1.0 
# >> _slice is similar to _regex 

結果爲單個字符結尾的字符:

compare do 
    _slice { STR[-1] == 'z' } 
    _end_with { STR.end_with?('z') } 
    _regex { !!STR[/z$/] } 
end 

# >> Running each test 32768 times. Test will take about 2 seconds. 
# >> _end_with is faster than _slice by 2x ± 1.0 
# >> _slice is faster than _regex by 2x ± 1.0 

結果結尾的字符串的多個字符:

compare do 
    _slice { STR[-5..-1] == 'vwxyz' } 
    _end_with { STR.end_with?('vwxyz') } 
    _regex { !!STR[/vwxyz$/] } 
end 

# >> Running each test 16384 times. Test will take about 1 second. 
# >> _end_with is faster than _slice by 2x ± 1.0 
# >> _slice is similar to _regex 

所以,清晰度和速度和end_with?應該是我們的第一選擇。如果我們需要使用模式,那麼切片或使用正則表達式是明顯的選擇。

+0

基準測試有意義。期待start_with?和end_with?更快,因爲它們可能不會構建任何字符串並將其返回給您,並可以對字符串本身進行比較。 – Mircea

+0

'start_with?'和'end_with?'的速度很快的原因是因爲它們已經被編譯並正在使用'memcmp()',而沒有被解釋,並且不依賴調用正則表達式引擎。換句話說,他們依靠C函數來比較字符/字節,這些字符/字節快速變暗。 –

+0

我相信我們同意:)(即說同樣的事情) – Mircea

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