mysqli返回的行數不正確

Question

我正在爲我的網站和我的生活寫一個'喜歡'的功能，我無法使用此功能！

假設這是一個簡化版本，我的數據庫結構：

ID --- POST_ID --- USER_ID

1 --- 1 ----------- 1

2 --- 2 ----------- 1

這是我寫的代碼：

public function userHasLikedPost($post_id,$user_id){ 
     $this->post_id_clean = sanitize($post_id); 
     $this->user_id_clean = sanitize($user_id); 

     global $mysqli,$db_table_prefix; 
     $stmt = $mysqli->prepare("SELECT like_type FROM ".$db_table_prefix."post_likes WHERE user_id = ? AND post_id = ?"); 

     $stmt->bind_param("ii", $this->post_id_clean, $this->user_id_clean); 

     $stmt->execute(); 
     $stmt->store_result(); 

     $stmt->bind_result($like_type); 

     $stmt->fetch(); 
     $result; 

     if($stmt->num_rows >0){ 
      $result = array("liked" => 1, "like_type" => $like_type); 
     }else{ 
      $result = array("liked" => 0); 
     } 

     return print_r($stmt); 

     $stmt->close(); 
    } 

當我打電話userHasLikedPost（1,1）我的代碼將返回正確行數

mysqli_stmt對象（[affected_rows] => 1 [INSERT_ID] => 0 [NUM_ROWS] = > [param_count] => 2 [field_count] => 1 [errno] => 0 [error] => [error_list] => Array（）[sqlstate] => 00000 [id] => 5）1

但是，如果我呼叫userHasLikedPost（2,1），我會得到不正確的行數。

mysqli_stmt對象（[affected_rows] => 0 [INSERT_ID] => 0 [NUM_ROWS] => [param_count] => 2 [FIELD_COUNT] => 1 [錯誤] => 0 [錯誤] => [error_list] => Array（）[sqlstate] => 00000 [id] => 5）1

這是怎麼回事？我正確使用mysqli嗎？數據存在於數據庫中，如果我在PHPMyAdmin中手動運行查詢，我將得到正確的輸出。我花了2個小時試圖讓這一個功能工作......預先感謝任何回覆:)

Answer 1

我解決了我的問題。我的綁定是錯誤的順序：/多麼尷尬哈哈！

解決方案：

替換這行代碼：

$stmt->bind_param("ii", $this->post_id_clean, $this->user_id_clean); 

有了：

$stmt->bind_param("ii", $this->user_id_clean, $this->post_id_clean);