我想要寫一段代碼,它將處理GraphQL查詢,像這樣:爲什麼在此GraphQL設置中不調用DataFetcher?
query {
group(id: "com.graphql-java")
name(name: "graphql-java")
version(id: "2.3.0")
}
我創建了一個數據提取器,把一個斷點get
方法中:
import graphql.schema.DataFetcher;
import graphql.schema.DataFetchingEnvironment;
public class TestDataFetcher implements DataFetcher {
public Object get(final DataFetchingEnvironment dataFetchingEnvironment) {
return null;
}
}
然後我寫了下面的代碼:
public class Example02 {
public static void main(final String[] args) throws IOException {
final Example02 app = new Example02();
app.run();
}
void run() throws IOException {
final TestDataFetcher testDataFetcher = new TestDataFetcher();
final List<GraphQLFieldDefinition> fields = Lists.newArrayList(
createGroupField(testDataFetcher),
createNameField(),
createVersionField());
final GraphQLObjectType queryType = newObject()
.name("query")
.fields(fields)
.build();
final GraphQLSchema schema = GraphQLSchema.newSchema()
.query(queryType)
.build();
final String query = FileUtils.readFileToString(
new File("src/main/resources/query1.txt"),
"UTF-8"
);
final Map<String, Object> result = (Map<String, Object>) new GraphQL(schema).execute(query).getData();
System.out.println(result);
}
private GraphQLFieldDefinition createVersionField() {
return newFieldDefinition().type(GraphQLString).name("version").build();
}
private GraphQLFieldDefinition createNameField() {
return newFieldDefinition().type(GraphQLString).name("name").build();
}
private GraphQLFieldDefinition createGroupField(TestDataFetcher testDataFetcher) {
final GraphQLArgument idArg = newArgument().name("id").type(GraphQLString).build();
return newFieldDefinition()
.type(GraphQLString)
.name("group")
.dataFetcher(testDataFetcher)
.argument(idArg)
.build();
}
}
當我在調試模式下運行main
方法,斷點不激活d。
爲什麼?我該如何解決它?
無論 –
\ n是簡單的空白,它都與'\ n'一起工作。這是一條新的路線。 –