Mysqli查詢不起作用

我想檢索一年中所有最大的疾病使用情況。我有一個名爲view_accepted_appoinments的表，它有列疾病和日期。我想這個查詢，但它不工作Mysqli查詢不起作用

select distinct doc_specilization as disease, 
DATE_FORMAT(date,'%Y') as year, 
count(Distinct doc_specilization) as count 
from view_accepted_appoinments 
group by year 
order by year desc;

查詢返回這裏面給出錯誤的病名

+--------------+------+-------+ 
| disease  | YEAR | count | 
+--------------+------+-------+ 
| Primary Care | 2014 |  8 | 
| Primary Care | 2013 |  1 | 
+--------------+------+-------+

來源

2014-12-13 Zeeshan

在這個意義上不工作？？你可以更清楚地瞭解你所得到的錯誤信息，或者顯示的數據與你所期望的輸出不同，並且你也可以向我們顯示錶格的列 – ManojGeek 2014-12-13 17:00:20

這個查詢是否在執行時返回你預期的記錄集通過像MySQL Workbench或phpMyAdmin這樣的數據庫客戶端？ – budhajeewa 2014-12-13 17:02:16

你可以分享一些樣本數據和你試圖達到的結果嗎？ – Mureinik 2014-12-13 17:04:59

select distinct d , spec,c from(
     select date_format(date,"%Y") as d, 
     doctor, doc_specilization as spec, 
     count(doc_specilization) as c from 
     view_accepted_appoinments 
     group by doc_specilization, d)f 
     group by d;

來源

2014-12-13 17:57:37

嘗試

SELECT doc_specialization AS disease, 
DATE_FORMAT(date, '%Y') AS year, 
COUNT(doc_specialization) AS count, 
FROM view_accepted_appoinments 
GROUP BY doc_specialization, year 
ORDER BY year DESC, doc_specialization ASC;

來源

2014-12-13 17:08:35 budhajeewa

發生此錯誤您的SQL語法錯誤;請檢查與您的MySQL服務器版本相對應的手冊，以便在第4行的'FROM view_accepted_appoinments GROUP BY doc_specialization，year ORDER BY D'附近使用正確的語法。 – Zeeshan 2014-12-13 17:11:55

@Zeeshan：您是否可以提供轉儲 - 最好帶有少量數據庫的實際數據？所以我可以導入它並測試？ – budhajeewa 2014-12-13 17:14:36

我爲此創建了一個邏輯表（視圖）。 – Zeeshan 2014-12-13 17:19:52

Mysqli查詢不起作用

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