2013-12-10 31 views
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下面是我的PHP代碼,我試圖添加電子郵件變量內的身體和發送電子郵件,但每當我嘗試運行該文件我不能?爲什麼?如果我刪除電子郵件的變量文件運行正常?我該如何解決它?PHP電子郵件變量不顯示,出現錯誤

$body='<img src="images\logo.jpg" alt="logo"/><br/>Howdy, <br/> <br/> We need to make sure   you are human,Please verify your email,To confirm your order with us!.<br/><b>Happy Shopping! </b> <br/> <br/> <a href="'.$base_url.'activation/'.$activation.'">'.$base_url.'activation/'.$activation.'</a><br/><br/>Best Regards,<br/>Zenolaps.com<br/>This Email Was Sent To"' echo $email'"'; 
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如果您收到一個錯誤,你能不能把它添加到這個問題?儘管您可能想查看如何在PHP中執行字符串連接,以及單引號和雙引號字符串之間的區別 – andrewsi

回答

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  1. 變化echo $email'.$email;

  2. Turn on error reporting,因爲它會告訴你什麼是錯的。 A 始終在開發過程中打開了錯誤報告以顯示所有錯誤。

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並添加連接。 ''這封電子郵件已發送至''。'email。''';' – Jessica

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好通話傑西卡 –

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謝謝約翰先生和謝謝傑西卡小姐:) – user3087528

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新增級聯This Email Was Sent To '.$email;

$body='<img src="images\logo.jpg" alt="logo"/><br/>Howdy, <br/> <br/> We need to make sure   you are human,Please verify your email,To confirm your order with us!.<br/><b>Happy Shopping! </b> <br/> <br/> <a href="'.$base_url.'activation/'.$activation.'">'.$base_url.'activation/'.$activation.'</a><br/><br/>Best Regards,<br/>Zenolaps.com<br/>This Email Was Sent To '.$email; 
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謝謝:)你們倆都很棒:) – user3087528