的Java String []數組去除特殊字符

Question

如何在s[0,2]location(818001,818002)(151515,151515)指定以下字符串中刪除","並存儲再次串[]

String[] s = {"818001,818002","121212","151515,151515"}; 

Answer 1

你應該解釋更詳細的您的問題。

我想你想要的是這樣的：

s = '(818001,818002)(151515,151515)' //the string you have. 
s = s.replace(')(',',').replace('(','').replace(')','');// output "818001,818002,151515,151515" 
final_string = s.split(','); //output (4) ["818001", "818002", "151515", "151515"] 

Answer 2

如果您需要在您的字符串數組中刪除逗號（或其他任何字符爲此事）指數最簡單的是通過數組和使用迭代String.replace()：

String[] s = {"818001,818002","121212","151515,151515"}; 
for(int i=0; i<s.length; i++) { 
    s[i] = s[i].replace(",", ""); 
} 
System.out.print(Arrays.toString(s)); // [818001818002, 121212, 151515151515]