如果有多個條件else語句

Question

什麼，我試圖做我的SQL查詢之前設置正確的變量。這是我創建的if語句，但我無法正確回顯。下面提供的設置應該回顯出fnm，但是會回顯nm。我在做什麼錯誤這裏有兩個變量匹配每個if語句，所以我可以插入正確的數據

$type = "No Notification"; 
$remote = "Yes"; 
if ($type == "No Notification" && $remote == "No"){ 
$type = "nm"; 
} 
elseif ($type == "Email Notification" && $remote == "No"){ 
$type = "m"; 
} 
elseif ($type == "No Notifcation" && $remote == "Yes"){ 
$type = "fnm"; 
} 
elseif ($type == "Email Notification" && $remote == "Yes"){ 
$type = "fm"; 
} 
else { 
$type = "nm"; 
} 

echo $type; 

Answer 1

你的第二個ELSEIF有一個錯字：Notifcation應該通知 這些事情發生:)