2015-07-05 21 views
-1

我想限制正在上傳的jpg文件,但它不工作。這是我上傳的代碼。在php中的文檔和PDF文件限制

<?php 
include "admin/includes/connect.php"; 


if(isset($_POST['btn-upload'])) 
{ 

$file = rand(1000,100000)."-".$_FILES['file']['name']; 
    $file_loc = $_FILES['file']['tmp_name']; 
$file_size = $_FILES['file']['size']; 
$file_type = $_FILES['file']['type']; 
    $name = $_POST['name']; 

    $email = $_POST['email']; 

    $allowedExts = array("pdf", "doc"); 
$temp = explode(".", $_FILES["file"]["name"]); 
$extension = end($temp); 
if (($_FILES["file"]["type"] == "application/pdf") 
|| ($_FILES["file"]["type"] == "application/doc") 
&& ($_FILES["file"]["size"] < 200000) 
&& in_array($extension, $allowedExts)) 
    { 
    if ($_FILES["file"]["error"] > 0) 
    { 
    echo "Return Code: " . $_FILES["file"]["error"] . "<br>"; 
    }} 




$folder="uploads/"; 

move_uploaded_file($file_loc,$folder.$file); 

$sql="INSERT INTO upload(name,email,file,type,size) VALUES('$name','$email','$file','$file_type','$file_size')"; 
    mysqli_query($conn, $sql); 

} 
?> 

回答

1
在本地( php.ini
變化

file_uploads = On 

然後HTML表單應該是這樣的

<form action="upload.php" method="post" enctype="multipart/form-data"> 
    Select files to upload: 
    <input type="file" name="UploadFile" id="UploadFile"> 
    <input type="submit" value="Upload File" name="submit"> 
</form> 

然後在upload.php

<?php 
    $path_to_move = "../uploads/pdf";//give your folder name 
    $file = $path_to_move . basename($_FILES["UploadFile"]["name"]); 
    $status = 1; 
    $FileType = pathinfo($file,PATHINFO_EXTENSION); 

    // Check the uploaded file size 
    if ($_FILES["UploadFile"]["size"] > 500000)//500000 = 500kb 
    { 
     echo "File is too large.";//error message 
     $status = 0;//Change this to 
    } 

    // Validate file Format 
    if($FileType != "pdf" && $FileType != "doc" && $FileType != "docx") 
    { 
     echo "Only PDF, doc or docx file Formats are allowed.";//error message 
     $status = 0;//Change this to 
    }  

    // Uploading file 
     if ($status == 0) 
     { 
      echo "Upload Failed";   
     } 
     else 
     { 
      if (move_uploaded_file($_FILES["UploadFile"]["tmp_name"], $path_to_move)) 
      { 
       echo "File uploaded"; 
      } else 
      { 
       echo "Error in uploading your file. Try Again"; 
      } 
     } 
?> 

從閱讀中獲得想法W3schools Site

+0

謝謝......... – Zeshan

+0

@Zeshan歡迎好友 –