如果不是「」空

Question

我試圖用CI寫一個說法，但我有寫WHERE is not = " "

我能有一個示例的問題，我至今都

$empty = array(''); 
$this->db->where_not_in("$this->_table['shop_shipping_rules']}.shop_shipping_rule_name", $empty); 

Answer 1

嘗試對簡單where()

$this->db->where("$this->_table['shop_shipping_rules']}.shop_shipping_rule_name !='' OR 
$this->_table['shop_shipping_rules']}.shop_shipping_rule_name IS NOT NULL 
"); 

編輯

$this->db->select('*'); 
$this->db->from('mytable'); 
$this->db->where("shop_shipping_rule_name IS NOT NULL AND shop_shipping_rule_name !=''") 
$query = $this->db->get(); 

OR

$this->db->select('*'); 
$this->db->from('mytable'); 
$this->db->where(" TRIM(shop_shipping_rule_name) IS NOT NULL AND TRIM(shop_shipping_rule_name) !=''") 
$query = $this->db->get(); 

Active Record Class

Mysql TRIM()

Answer 2

嘗試這樣的事：

$this->db->where('field_name IS NOT NULL'); 

或者這樣說：

$this->db->where('field_name !=' , ''); 

Answer 3

只需使用""與where

$this->db->where("$this->_table['shop_shipping_rules']}.shop_shipping_rule_name !=", "");