HangMan錯誤輸出

Question

我似乎有一個問題，我不能修復，當用戶輸入完整的單詞爲我的程序時，它顯示每次搜索字符，而不是隻顯示整個單詞說他們已經猜對了。我怎樣才能讓它只顯示單詞而不顯示每次搜索的時候用戶輸入整個單詞的字符？感謝未來的回信

package assignment1Q2; 

import java.io.File; 
import java.io.FileNotFoundException; 

import java.util.Scanner; 
public class HangmanClassExample { 

static Scanner keyboard = new Scanner(System.in); 
static int play, size, size2; 
static String word; 
static String[] ARRAY = new String[0]; 


public static void main(String[] args) { 

    setUpGame(); 
} 

public static void setUpGame() { 
    System.err.printf("Welcome to hangman.\n"); 

    try { 

     Scanner scFile = new Scanner(new File("H:\\Varsity work\\Java Programming\\Programs\\HangMan\\src\\hangman\\HangMan.txt")); 
     String line; 
     while (scFile.hasNext()) { 
      line = scFile.nextLine(); 
      Scanner scLine = new Scanner(line); 
      size++; 
     } 
     ARRAY = new String[size]; 
     Scanner scFile1 = new Scanner(new File("H:\\Varsity work\\Java Programming\\Programs\\HangMan\\src\\hangman\\HangMan.txt")); 
     while (scFile1.hasNext()) { 
      String word; 
      line = scFile1.nextLine(); 
      Scanner scLine = new Scanner(line); 
      word = scLine.next(); 
      ARRAY[size2] = word; 
      size2++; 
      calculateGuess(); 
     } 
    } catch (FileNotFoundException e) { 
     System.out.println(e); 
    } 
} 

public static void calculateGuess() { 

    try { 
     do { 

      int random = (int) (Math.random() * ARRAY.length); 
      String randomWord = ARRAY[random]; 
      String word = randomWord; 
      char[] ranWord = randomWord.toCharArray(); 
      char[] dash = word.toCharArray(); 

      int LEFT = 6; 
      for (int i = 0; i < dash.length; i++) { 
       dash[i] = '-'; 
       System.out.print(dash[i]); 
      } 
     for (int A = 1; A <= dash.length;) { 
      System.out.print("\nGuess a Letter:"); 
      String userletters = keyboard.next();; 

      for (int i = 0; i < userletters.length(); i++) { 
       char userLetter = userletters.charAt(i); 
       String T = Character.toString(userLetter); 
       for (int B = 0; B < ranWord.length; B++) { 

        if (userLetter == dash[B]) { 
         System.out.println("this '" + userLetter + "' letter already exist"); 
         B++; 
         if (userLetter == dash[B-1]) { 
          break; 
         } 


        } else if (userLetter == ranWord[B]) { 
         dash[B] = userLetter; 
         A--; 
        } 
       } 
       if (!(new String(ranWord).contains(T))) { 
        LEFT--; 
        System.out.println("You did not guess a correct letter, you have " + LEFT + " OF " 
          + dash.length + " trys left to guess correctly"); 
       } 

       System.out.println(dash); 
      } 
      if ((new String(word)).equals(new String(dash))) { 
       System.out.println("\nYou have guessed the word correctly!"); 
       break; 

      } 

     } 

      System.out.println("Play agian? (y/n)"); 
      String name = keyboard.next(); 

      if (name.equals("y")) { 
       play = 0; 

      } else { 
       play = 1; 
       return; 
      } 
     } while (play == 0); 

    } catch (NullPointerException e) { 

    } 
} 

}

OUTPUT：

Welcome to hangman. 



-------- 

Guess a Letter:c 

c------- 

Guess a Letter:c 

this 'c' letter already exist 

c------- 

Guess a Letter:computer 

this 'c' letter already exist 

c------- 

co------ 

com----- 

comp---- 

compu--- 

comput-- 

compute- 

computer 

You have guessed the word correctly! 

Play agian? (y/n) 

n 

Answer 1

有兩個for循環和檢查每個字符，而不是，您可以使用startsWith檢查字符用戶輸入。對於例如如果用戶輸入comp，則可以簡單地檢查originalString.startsWith(comp) - 如果爲true，則只需打印補償並從originalString中刪除前4個字符。

Answer 2

你可以採取如果你的爲循環這樣

 if ((new String(word)).equals(new String(dash))) { 
      System.out.println("\nYou have guessed the word correctly!"); 
      // break; not needed anymore as we're out of the loop 

     } 
     else { 
      for (int i = 0; i < userletters.length(); i++) { 
      char userLetter = userletters.charAt(i); 
      String T = Character.toString(userLetter); 
      for (int B = 0; B < ranWord.length; B++) { 

       if (userLetter == dash[B]) { 
        System.out.println("this '" + userLetter + "' letter already exist"); 
        B++; 
        if (userLetter == dash[B-1]) { 
         break; 
        } 


       } else if (userLetter == ranWord[B]) { 
        dash[B] = userLetter; 
        A--; 
       } 
      } 
      if (!(new String(ranWord).contains(T))) { 
       LEFT--; 
       System.out.println("You did not guess a correct letter, you have " + LEFT + " OF " 
         + dash.length + " trys left to guess correctly"); 
      } 

      System.out.println(dash); 
     } 
    } 

}的

但在我看來，在那樣的遊戲，用戶應該只能夠輸入一個字符而不是整個單詞。