1
所以我有一個自定義對象的數組。我想通過他們去找到maxx,maxy,minx和miny值。我需要最大和最小的分鐘。下面的代碼對我來說是完全有意義的,但是我傾向於從列表中獲得一個隨機值,我的最大值沒有得到最大值或最小值,而分值沒有得到最小值或最大值。獲取最小值和最大值
因此,我從數組中的第一個對象中取出第一個值,然後將每個對象值與我當前的maxx,maxy,minx,miny進行比較,以查看對象的值是大於還是小於,如果是,其分配:
claimCenterBoundary = [dataCenter.claimCenterBoundaryList objectAtIndex:0];
maxx = claimCenterBoundary.maxx;
maxy = claimCenterBoundary.maxy;
minx = claimCenterBoundary.minx;
miny = claimCenterBoundary.miny;
for (int i = 0; i < count; i++)
{
claimCenterBoundary = [dataCenter.claimCenterBoundaryList objectAtIndex:i];
NSLog(@"minx: %@ miny: %@ maxx: %@ maxy: %@", claimCenterBoundary.minx, claimCenterBoundary.miny, claimCenterBoundary.maxx, claimCenterBoundary.maxy);
if (maxx < claimCenterBoundary.maxx)
maxx = claimCenterBoundary.maxx;
if (maxy < claimCenterBoundary.maxy)
maxy = claimCenterBoundary.maxy;
if (minx > claimCenterBoundary.minx)
minx = claimCenterBoundary.minx;
if (miny > claimCenterBoundary.miny)
miny = claimCenterBoundary.miny;
}
這裏是我的輸出:
count: 8
minx: -98.9139404296875 miny: 48.51737594604492 maxx: -98.90547943115234 maxy: 48.52248382568359
minx: -98.9139404296875 miny: 48.51737594604492 maxx: -98.90547943115234 maxy: 48.52248382568359
minx: -98.92726898193359 miny: 48.51534652709961 maxx: -98.91975402832031 maxy: 48.52249908447266
minx: -98.92726898193359 miny: 48.51534652709961 maxx: -98.91975402832031 maxy: 48.52249908447266
minx: -98.92340850830078 miny: 48.51531219482422 maxx: -98.91383361816406 maxy: 48.52248382568359
minx: -98.92340850830078 miny: 48.51531219482422 maxx: -98.91383361816406 maxy: 48.52248382568359
minx: -98.909423828125 miny: 48.51529693603516 maxx: -98.90548706054688 maxy: 48.51742553710938
minx: -98.96006774902344 miny: 48.51530075073242 maxx: -98.94926452636719 maxy: 48.52977752685547
final minx :-98.92726898193359 miny: 48.51531219482422 maxx: -98.94926452636719 maxy: 48.52977752685547
我想不通爲什麼這個代碼是行不通的。
+1,但希望能看到一個博客文章告訴我們如何實現' - (NSArray的*)valuesForKeyPaths:(NSArray的*)paths'現在有效的任何一天... ;-) – Caleb
+1這聽起來好多了比我的回答,看起來是正確的。 – chown
作品很有魅力,非常感謝! – Padin215