比較兩個數組並找到SWIFT 3中非常見元素的索引

Question

數組的類型爲字符串。由於添加「」很費時，所以我寫它像Int。抱歉。

我有兩個陣列說var array1 = [[1,2,3,4,5,6,7,8,9]]和

var array2 = [[1,2,3,4], 
       [2,3,4,5], 
       [2,4,5,6], 
       [1,2,3,4,5,6,7,8,9], 
       [1,2,3,4,5,6,7,8], 
       [2,3,4,5,6,7,8]] 

我必須的array2每個數組元素與array1比較，並插入「 - 」其中元素不匹配。與此類似，

var array2 = [[1,2,3,4,-,-,-,-,-], 
       [-,2,3,4,5,-,-,-,-], 
       [-,2,-,4,5,6,-,-,-], 
       [1,2,3,4,5,6,7,8,9], 
       [1,2,3,4,5,6,7,8,-], 
       [-,2,3,4,5,6,7,8,-]] 

我試圖遍歷數組2中每個陣列，並將其與數組1比較，比較的指標，並插入「 - 」索引位置我，但我得到意想不到的效果。

UPDATE

for item in array2{ 
var elementsArray = item 
for i in stride(from: 0, to: elementsArray.count, by: 1) { 
    if elementsArray[i] != array1[i] 
    { 
     elementsArray.insert("-", at: i) 
    } 
    print("elemnt array.....", elementsArray, "\n\n") 
} 
} 

我曾認爲通過count與ARRAY1數組2的每個陣列比較，發現罕見元素的索引，然後插入「 - 」在該索引位置。這種方法是對的嗎？請幫我解決一下這個。

Answer 1

你想要一個新的數組，其中的array2每行是由 array1變體取代，元素最初不存在被替換的行中「 - 」：

let array1 = [1,2,3,4,5,6,7,8,9] 
let array2 = [[1,2,3,4], 
       [2,3,4,5], 
       [2,4,5,6], 
       [1,2,3,4,5,6,7,8,9], 
       [1,2,3,4,5,6,7,8], 
       [2,3,4,5,6,7,8]] 

let filled = array2.map { row in 
    array1.map { 
     row.contains($0) ? String($0) : "-" 
    } 
} 

for row in filled { print(row) } 

輸出：

 
["1", "2", "3", "4", "-", "-", "-", "-", "-"] 
["-", "2", "3", "4", "5", "-", "-", "-", "-"] 
["-", "2", "-", "4", "5", "6", "-", "-", "-"] 
["1", "2", "3", "4", "5", "6", "7", "8", "9"] 
["1", "2", "3", "4", "5", "6", "7", "8", "-"] 
["-", "2", "3", "4", "5", "6", "7", "8", "-"] 

對於大型陣列，可以通過爲 創建Set(row)來更快地進行遏制檢查，或者通過利用元件 同時增加訂單。

您的方法無法正常工作，因爲elementsArray 在迭代它時被修改。