如何將`NSmutableArray`數組數組拆分爲swift 3？

Question

NSMutableArray *sample; 

我有一個NSmutableArray，我想分割成塊。我試圖檢查互聯網沒有找到它的解決方案。我得到了拆分整數數組的鏈接。

Answer 1

您可以使用subarray方法。

let array = NSArray(array: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) 

let left = array.subarray(with: NSMakeRange(0, 5)) 
let right = array.subarray(with: NSMakeRange(5, 5)) 

Answer 2

這怎麼樣，這是更Swifty？

let integerArray = [1,2,3,4,5,6,7,8,9,10] 
let stringArray = ["a", "b", "c", "d", "e", "f"] 
let anyObjectArray: [Any] = ["a", 1, "b", 2, "c", 3] 

extension Array { 
    func chunks(_ chunkSize: Int) -> [[Element]] { 
     return stride(from: 0, to: self.count, by: chunkSize).map { 
      Array(self[$0..<Swift.min($0 + chunkSize, self.count)]) 
     } 
    } 
} 

integerArray.chunks(2) //[[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] 
stringArray.chunks(3) //[["a", "b", "c"], ["d", "e", "f"]] 
anyObjectArray.chunks(2) //[["a", 1], ["b", 2], ["c", 3]] 

轉換NSMutableArray斯威夫特Array：

let nsarray = NSMutableArray(array: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) 
if let swiftArray = nsarray as NSArray as? [Int] { 
    swiftArray.chunks(2) //[[1, 2], [3, 4], [5, 6], [7, 8], [9, 10]] 
} 

如果你想堅持使用NSArray，則：

let nsarray = NSMutableArray(array: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) 

extension NSArray { 
    func chunks(_ chunkSize: Int) -> [[Element]] { 
     return stride(from: 0, to: self.count, by: chunkSize).map { 
      self.subarray(with: NSRange(location: $0, length: Swift.min(chunkSize, self.count - $0))) 
     } 
    } 
} 

nsarray.chunks(3) //[[1, 2, 3], [4, 5, 6], [7, 8, 9], [10]]