刪除從另一個文件

Question

我有一個csv文件（list.csv）包含ID的每一行，至極含有類似的東西：

"1","10","1","2" 
"2","22","20","2" 
"3","33","5","2" 
"4","36","225","2" 
"5","36","225","2" 

我有另一個文件（delete.txt）：

"1" 
"4" 

我想從delete.txt文件中刪除包含ID的每一行。 在我的示例中，我想顯示：

"2","22","20","2" 
"3","33","5","2" 
"5","36","225","2" 

我該怎麼做？謝謝:)

Answer 1

在單次使用grep（你可以在結束時，如果你想看到使用的查詢添加echo "$arg"）：

#!/bin/bash 
arg="" 
for i in `cat delete.txt`; do 
     if [ -n "$arg" ]; then 
       arg="$arg\|^$i" 
     else 
       arg="^$i"; 
     fi 
done; 
grep -v "$arg" input.txt 

Answer 2

你可以試試這個：

< delete.txt xargs -I % sed -i '/%/d' list.csv 

它從delete.txt中讀取所有行，傳遞給sed以進行刪除。