當我嘗試發送附件使用indy的電子郵件時,我的程序凍結,我不知道爲什麼。 以下是我用於發送電子郵件的表單的完整代碼。使用Indy無法發送電子郵件,凍結程序
unit Dok_sutisana;
interface
uses
Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
Dialogs, IdMessage, IdBaseComponent, IdComponent, IdTCPConnection,
IdTCPClient, IdExplicitTLSClientServerBase, IdMessageClient, IdSMTPBase,
IdSMTP, StdCtrls, Buttons, ComCtrls, IdAttachmentFile;
type
TForm14 = class(TForm)
Edit1: TEdit;
Edit2: TEdit;
Label1: TLabel;
Label2: TLabel;
BitBtn1: TBitBtn;
FontDialog1: TFontDialog;
RichEdit1: TRichEdit;
IdSMTP1: TIdSMTP;
IdMessage1: TIdMessage;
BitBtn2: TBitBtn;
procedure BitBtn2Click(Sender: TObject);
procedure BitBtn1Click(Sender: TObject);
private
{ Private declarations }
public
{ Public declarations }
end;
var
Form14: TForm14;
implementation
uses Autentif, EDGA;
{$R *.dfm}
procedure TForm14.BitBtn1Click(Sender: TObject);
begin
if FontDialog1.Execute() then
RichEdit1.Font:=FontDialog1.Font;
end;
procedure TForm14.BitBtn2Click(Sender: TObject);
var s:string;
begin
form3.ADOTable1.Active:=true;
//setup SMTP
IdSMTP1.Host := form3.adotable1['smtp'];
IdSMTP1.Port := form3.adotable1['ports'];
IdSMTP1.Username:= '******@gmail.com';
IdSMTP1.Password:='******';
//setup mail message
IdMessage1.From.Address := form3.adotable1['e-pasts'];
IdMessage1.From.Name:= form3.adotable1['Vards']+' '+ form3.adotable1['Uzvards'];
IdMessage1.Recipients.EMailAddresses := edit1.Text;;
IdMessage1.Subject := edit2.Text;
IdMessage1.Body.Add(RichEdit1.Text + form3.ADOTable1['paraksts']);
s:= GetCurrentDir + form1.ADOTable1['Dok_adr'];
TIdAttachmentFile.Create(IdMessage1.MessageParts, s) ;
//send mail
IdSMTP1.Connect() ;
IdSMTP1.Send(IdMessage1) ;
IdSMTP1.Disconnect;
IdMessage1.Free;
IdSMTP1.Free;
form3.ADOTable1.Active:=false;
Form14.Close;
end;
end.
我希望惠普,我可以得到一些幫助我的問題。
你有沒有嘗試用調試器逐步通過你的代碼?可能有助於確切知道哪一步鎖定。你也需要嘗試......最後圍繞連接/斷開連接和內存創建/釋放。可能是第一次通過你連接,但不要斷開,然後你將不得不等待連接超時。 – DavidG
@DavidG鎖定發生在IdSMTP TIdSMTP.Connect函數中 – sistemcrash
當我使用這個庫時,我有另外一行:「IdSMTP1.NeedAuthentication:= false;」和「IdSMTP1.UseTLS:= emNOTLSSupport」。我懷疑你可以在連接之前嘗試第一行,看看會發生什麼。 – DavidG