sqlite3.InterfaceError：錯誤綁定參數0 - 可能是不支持的類型

Question

我寫這在SQLite數據庫中存儲數據的代理爬行，我更喜歡通過語句來保存複雜的物體，像cur.execute("insert into test(p) values (?)", (p,))
後來我找到一個有用的正式文件here
官方文檔中的例子效果很好。
但是有一個問題來找我。
我的官方代碼更改爲：

import sqlite3 
import time 

class Proxy: 
    def __init__(self,ip,port,speed,area,level,active,last_check_time): 
     self.ip = ip 
     self.port = port 
     self.speed = speed 
     self.area = area 
     self.level = level 
     self.active = active 
     self.last_check_time = last_check_time 
    def __repr__(self): 
     return '%s;%s;%s;%s;%s;%d;%d' % (self.ip,self.port,self.speed,self.area,self.level,self.active,self.last_check_time) 



def adapt_proxy(proxy): 
    return '%s;%s;%s;%s;%s;%d;%d' % (proxy.ip,proxy.port,proxy.speed,proxy.area,proxy.level,proxy.active,proxy.last_check_time) 

def convert_proxy(s): 
    ip,port,speed,area,level,active,last_check_time = map(str, s.split(";")) 
    return Proxy(ip,port,speed,area,level,int(active),int(last_check_time)) 


# Register the adapter 
sqlite3.register_adapter(Proxy, adapt_proxy) 

# Register the converter 
sqlite3.register_converter("proxy", convert_proxy) 

p = Proxy('231', '123', '2424','444','555',1,int(time.time())) 

######################### 
# 1) Using declared types 
con = sqlite3.connect(":memory:", detect_types=sqlite3.PARSE_DECLTYPES) 
cur = con.cursor() 
cur.execute("create table test(p proxy)") 

cur.execute("insert into test(p) values (?)", (p,)) 
cur.execute("select p from test") 
print "with declared types:", cur.fetchone()[0] 
cur.close() 
con.close() 

####################### 
# 1) Using column names 
con = sqlite3.connect(":memory:", detect_types=sqlite3.PARSE_COLNAMES) 
cur = con.cursor() 
cur.execute("create table test(p)") 

cur.execute("insert into test(p) values (?)", (p,)) 
cur.execute('select p as "p [proxy]" from test') 
print "with column names:", cur.fetchone()[0] 
cur.close() 
con.close() 

發生錯誤：

Traceback (most recent call last): 

    File "C:\Users\kss\Desktop\py\ts1.py", line 52, in <module> 
    cur.execute("insert into test(p) values (?)", (p,)) 
sqlite3.InterfaceError: Error binding parameter 0 - probably unsupported type. 
[Finished in 0.1s with exit code 1] 

這實在是odd.I無法弄清楚它

Answer 1

更改代理的聲明：

class Proxy(object): 
    # all the stuff before 

問題是你的班級不是「新風格」的班級;從object繼承使之成爲一體。

注意如何documentation說：

The type/class to adapt must be a new-style class, i. e. it must have object as one of its bases.